This is a very poorly written question. im assuming the house wall is at least 130 ft since there is no information given about it.
each set of side lengths has three elements, the long side and the two short sides. we're asked to list all whole number possibilities so start anywhere, the two short sides being 1ft
(1 1 130). the long side has to be the difference of 132 and the length of both short sides.
the area is one of the short sides times the ling side, in the first case 1*130=130 sqft
continuing the list
(2 2 128) area=256
(3 3 126) area=378
(4 4 124) area=496
(5 5 122) area=610
the short sides increase by 1, the long side decreases by 2, the area gets bigger, but the difference between the areas are 4 less each time. dividing the first difference, 122, by 4 will give us a number to make a better guess from.
122÷4=30.5
so lets try
(30 30 72) area=2160
lets try 31 and see if that gives a smaller area
(31 31 70) area = 2170
(32 32 68) area =2176
(33 33 66) area = 2178
(34 34 64) area = 2176
so the area is decreasing now which means the maximum area is found when thw long side is 66 feet and the short sides are 33 feet.
as far as listing all possibilities, you see the pattern i started, i leave the rest to you
The answer is 40 is 80% of 50 ☺
Answer:
0.2364
Step-by-step explanation:
We will take
Lyme = L
HGE = H
P(L) = 16% = 0.16
P(H) = 10% = 0.10
P(L ∩ H) = 0.10 x p(L U H)
Using the addition theorem
P(L U H) = p(L) + P(H) - P(L ∩ H)
P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)
P(L U H) = 0.26 - 0.10p(L u H)
We collect like terms
P(L U H) + 0.10P(L U H) = 0.26
This can be rewritten as:
P(L U H)[1 +0.1] = 0.26
Then we have,
1.1p(L U H) = 0.26
We divide through by 1.1
P(L U H) = 0.26/1.1
= 0.2364
Therefore
P(L ∩ H) = 0.10 x 0.2364
The probability of tick also carrying lyme disease
P(L|H) = p(L ∩ H)/P(H)
= 0.1x0.2364/0.1
= 0.2364
Answer:
4
Step-by-step explanation:
The square root of 16 is four since 4 x 4 is 16.
