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choli [55]
3 years ago
10

I need help with find the area of the other shapes. Like you can give me an example of the width and lenth like this (8:7) and I

'll put a pic of what I've got so far and I need you to do what I did please.I really need help.
You must include the following items: • At least 10 shapes in which you can calculate the area (label the dimensions for each shape in feet 1 cm=3.25feet) o 2 rectangles o 1 rhombus o 3 triangles (1 must include a fractional base) o 2 trapezoids (1 base must be a decimal) o 1 pentagon o 1 irregular polygon in which you’ll have to decompose into smaller shapes. And if my pic ain't clear enough sorry.

Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
6 0
I am really not sure just tryna get my answers
Aleonysh [2.5K]3 years ago
5 0

Answer:

Step-by-step explanation:

Hmm i think you take the cm flee to the 8th

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A = 100(1+r)^4<br> Expand the right of this formula.<br> appreciate your help with an explanation
suter [353]

Answer:

100r^4 + 400r^3 + 600r^2 + 400r + 100

Step-by-step explanation:

Expanding ( r + 1 )^4 gives :-

r^4 + 4r^3 + 6r^2 + 4r + 1

So multiplying 100 with r^4 + 4r^3 + 6r^2 + 4r + 1 gives :-

100r^4 + 400r^3 + 600r^2 + 400r + 100

4 0
3 years ago
6. The diagram on the right shows the cross-section of a cylindrical pipe with water lying in the bottom. a) If the maximum dept
riadik2000 [5.3K]

Answer:

404 cm³ Anyway... Look down here for my explanation.

Step-by-step explanation:

Let's Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth on your paper. A right-angled triangle is formed too. The Length of side to the water-surface is 5 cm, the hospot is 7 cm.

We Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7)

44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8°

The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram.

Shaded area 88.8/360*area of circle - ½*7*788.8°

= 88.8/360*π*7² - 24.5*sin 88.8°

13.5 cm²

(using area of ∆ = ½.a.b.sin C for the triangle)

Volume of water = cross-sectional area * length

13.5 * 30 cm³

404 cm³

6 0
2 years ago
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