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Goryan [66]
3 years ago
9

Evaluate -8(x-3y) when x= -2 and y = -4 A. 112 B. 80 C.-80 D.-16

Mathematics
1 answer:
alexgriva [62]3 years ago
7 0
-8(-2--12)
-8(-2+12)
-8(10)
-80
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Can you please help me with this
UNO [17]
Parentheses. Exponents. Multiplication Division. Addition Subtraction.

2) 6 x (11 - 5)- 7^2
6 x (6) - 7^2
6 x 6 - 49
36 - 49
-13

3) (40 - 2^2) / (-4 + 6)
(40 - 4) / (-4 + 6)
(36) / (2)
36/2
13/1
13

4) (66 - 6) / 6 - 2^2
(60) / 6 - 2^2
60 / 6 - 4
60 / 2
30 / 1
30
4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B12%7D%20%20%5Cdiv%20%20%5Cfrac%7B2%7D%7B11%7D%20%20%3D%20" id="TexFormula1
katrin2010 [14]

Solve. To solve this equation, you must change the divide sign into a multiplication sign.

To do so, change it into a multiplication sign, and flip the second fraction

(5/12)/(2/11) = 5/12 x 11/2

Multiply across

5/12 x 11/2 = 55/24

55/24, or 4 7/12

hope this helps

<em>~Rise Above the Ordinary</em>

7 0
3 years ago
11. Health. Sherri is considering joining a health club. To be a member of Roman's Gym, she would
sergeinik [125]

Answer:

help

Step-by-step explanation:

4 0
2 years ago
Temperature transducers of a certain type are shipped in batches of 50. A sample of 58 batches was selected, and the number of t
andrew11 [14]

Answer:

a) X        Freq.         Rel Freq.

__________________________

0           7              (7/58) = 0.121

1            10            (10/58)=0.172

2           13            (13/58) =0.224

3           14            (14/58)=0.241

4           6              (6/58)=0.103

5           3              (3/58)=0.052

6           3              (3/58)=0.052

7            1              (1/58) =0.017

8            1              (1/58)=0.017

_________________________

Total     58                 1.00

b) \frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862

Step-by-step explanation:

Assuming this question: Temperature transducers of a certain type are shipped in batches of 50. A sample of 60 batches was selected, and the number of transducers in each batch not conforming to design specifications was determined, resulting in the following data:

2,1,2,4,0,1,3,2,0,5,3,3,1,3,2,4,7,0,2,3,

0,4,2,1,3,1,1,3,4,2,3,2,2,8,4,5,1,3,1,

5,0,2,3,2,1,0,6,4,2,1,6,0,3,3,3,6,2,3

(a) Determine frequencies and relative frequencies for the observed values of x = number of nonconforming transducers in a batch. (Round your relative frequencies to three decimal places.)

For this case first we order the dataset on increasing way and we got:

0 0 0 0 0 0 0

1 1 1 1 1 1 1 1 1 1

2 2 2 2  2 2 2 2 2 2 2 2 2

3 3 3 3 3 3 3 3 3 3 3 3  3 3

4 4 4 4 4 4

5 5 5

6 6 6

7

8

And we can construct the following table:

X        Freq.         Rel Freq.

__________________________

0           7              (7/58) = 0.121

1            10            (10/58)=0.172

2           13            (13/58) =0.224

3           14            (14/58)=0.241

4           6              (6/58)=0.103

5           3              (3/58)=0.052

6           3              (3/58)=0.052

7            1              (1/58) =0.017

8            1              (1/58)=0.017

_________________________

Total     58                 1.00

(b) What proportion of batches in the sample have at most four nonconforming transducers? (Round your answer to three decimal places.)

For this case this proportion would be:

\frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862

4 0
3 years ago
here are 5 cards: 2,5,7,8,9. one of the cards is removed and then mean average is 6. which card was removed
omeli [17]

Answer:

9 would be removed i believe

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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