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Greeley [361]
3 years ago
11

The coldest temperature ever

Mathematics
1 answer:
dedylja [7]3 years ago
8 0
Florida gets really hot sometimes soo I would get like a better air conditioner
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A photo is printed on an 12-inch by 18-inch piece of paper. The photo covers 112 square inches and has a uniform border. What is
ohaa [14]

Answer: the width of the border is 2 inches.

Step-by-step explanation:

The formula for determining the area of a rectangle is expressed as

Area = length × width

Let x represent the width of the border.

The photo is printed on an 12-inch by 18-inch piece of paper. The width of the photo will be (12 - 2x) inches. The length of the paper will be (18 - 2x) inches.

The area of the paper would be

(18 - 2x)(12 - 2x)

The photo covers 112 square inches and has a uniform border. This means that

(18 - 2x)(12 - 2x) = 112

216 - 36x - 24x + 4x² = 112

4x² - 60x + 216 - 112 = 0

4x² - 60x + 104 = 0

Dividing through by 4, it becomes

x² - 15x + 26 = 0

x² - 13x - 2x + 26 = 0

x(x - 13) - 2(x - 13) = 0

x - 2 = 0 or x - 13 = 0

x = 2 or x = 13

The only possible value for the width of the border is x = 2 inches

6 0
3 years ago
Need help please and thank you
earnstyle [38]
Anything you need specific help on? A specific question?

8 0
3 years ago
Read 2 more answers
Answers: <img src="https://tex.z-dn.net/?f=%5Cfrac%7B70%7D%7B3%7D" id="TexFormula1" title="\frac{70}{3}" alt="\frac{70}{3}" alig
kozerog [31]

Answer:

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Helppppppppp pleaseeeeeeeeeeeeeee
Elis [28]

Answer:

Number is yellow box=3

Step-by-step explanation:

We know this because the way we get that number is subtracting the two numbers above it, which is 8 and 5, which give us 3.

if you appreciated this, please consider giving me brainliest, it will help me a lot

Thank you,

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5 0
4 years ago
The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?
Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

A(-6, 2)) = (x_1, y_1)

B(2, 6) = (x_2, y_2)

AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}

AB = \sqrt{(8)^2 + (4)^2}

AB = \sqrt{64 + 16} = \sqrt{80}

AB = 8.9 (nearest tenth)

Distance between B(2, 6) and C(7, 1):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

B(2, 6) = (x_1, y_1)

C(7, 1) = (x_2, y_2)

BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}

BC = \sqrt{(5)^2 + (-5)^2}

BC = \sqrt{25 + 25} = \sqrt{50}

BC = 7.1 (nearest tenth)

Distance between C(7, 1) and D(3, -5):

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

C(7, 1) = (x_1, y_1)

D(3, -5) = (x_2, y_2)

CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}

CD = \sqrt{(-4)^2 + (-6)^2}

CD = \sqrt{16 + 36} = \sqrt{52}

CD = 7.2 (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

D(3, -5) = (x_1, y_1)

A(-6, 2) = (x_2, y_2)

DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}

DA = \sqrt{(-9)^2 + (7)^2}

DA = \sqrt{81 + 49} = \sqrt{130}

DA = 11.4 (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0
3 years ago
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