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algol13
3 years ago
5

I want to know the answer to this . I don’t really get it . so how would I get the answer ?

Mathematics
1 answer:
Lapatulllka [165]3 years ago
8 0

Answer:

0.444... (or 44.44...%)

Step-by-step explanation:

The experimental probability is the probability of an event actually happening. The experimental probability of a man having a beard here is 44.444...% (8/18).

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The coffee Lily likes is composed of 97.3% water and 2.7% cocoa. The coffee John likes is composed of 96% water and 4% cocoa. Ho
mestny [16]

30 ounces of the coffee John likes consists of

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  • 0.04\cdot30=1.2 ounces of cocoa

To this mixture we're adding x ounces of water, so that the new mix has a total volume of 30+x ounces and matches the composition of the coffee Lily likes. This means it would consist of

  • 0.973\cdot(30+x)=28.8+x ounces of water
  • 0.027\cdot(30+x)=1.2 ounces of cocoa (same amount of cocoa as before because pure water is being added)

Solve for x:

0.973(30+x)=28.8+x\implies29.12+0.973x=28.8+x

\implies0.39=0.027x

\implies x\approx14.4

###

Just to confirm: the new mixture consists of

  • 28.8+14.4=43.2 ounces of water
  • 1.2+0=1.2 ounces of cocoa

giving a total volume of 43.2+1.2=44.4 ounces of coffee, and \dfrac{43.2}{44.4}\approx0.973, as required.

4 0
4 years ago
Suppose n(x)= 22 and n(y) is 13 what is the maximum number of elements X ∪Y can have ?
Nikolay [14]
The inclusion/exclusion principle states that

|X\cup Y|=|X|+|Y|-|X\cap Y|

That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).

Therefore, |X\cup Y| will have the most elements when the sets X and Y are disjoint, i.e. X\cap Y=\emptyset, which would mean the most we can can in this case would be

|X\cup Y|=|X|+|Y|=22+13=35

(Note that n(X)=|X| denotes the cardinality of the set X.)
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4 years ago
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Answer:

(4,1)

Step-by-step explanation:

4 0
3 years ago
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i need help solving my homework it says : A rectangular prism has a length of 4 cm and a width of 5 cm. The volume of the prism
sashaice [31]
The volume is length * width * height.  Length * width is 4 * 5 or 20, so we have that 20 * height = 200.  Divide by 20 to get height = 10.
4 0
3 years ago
60 in<br> 63 in<br> What is the length of the hypotenuse?<br> inches<br> Submit
saveliy_v [14]

Answer:

assuming 60 and 63 are the side lengths

87 in is the hypotenuse

Step-by-step explanation:

60^2 + 63^2 = x^2

5 0
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