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3 years ago

Give the location of the elements found in the periodic table which have the same number of shells.

Chemistry

2 answers:

Katena32 [7]3 years ago

5 0

Answer:

Answer is B. All members within any group

zmey [24]3 years ago

3 0

B. All members within any group

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Ethyl alcohol has a heat of vaporization of 850. J/g. What mass of ethyl alcohol can be boiled using 15000 J of energy?

Verdich [7]

The amount of heat, H, needed to boil off certain mass, m, of the substance is given by the equation,
H = mHv
where Hv is the heat of vaporization. Manipulating the equation, the mass is calculated by,
m = H/Hv
Substituting the known values,
m = 15000 J/(850 J/g) = 17.65 g
Thus, the mass of ethyl alcohol is approximately 17.65 g.

3 0

4 years ago

Read 2 more answers

A 12.0 wt% solution of CaCl2 (110.98 g/mol) has a density of 1.107 g/mL.

mariarad [96]

Answer:

a) Mass of solution is 16,605 milli grams.

b) 57.29 grams is the mass of calcium chloride in 431.3 mL of a 12.0 wt% solution.

c) 1.1967 mol/L is the formal concentration of calcium chloride in 431.3 mL solution.

Explanation:

Mass by mass percentage of calcium chloride solution, wt% = 12.0%

Density of the solution = d = 1.107 g/mL

a) Volume of the solution , V= 15.0 mL

Mass of the solution = m

$Mass=density\times Volume$

$m=d\times V=1.107 g/ml\times 15.0 mL=16.605 g$

Mass of solution = 16.605 g = 16,605 mg (1g = 1000 mg)

b) Mass of the solution = m

Volume of the solution = V = 431.3 mL

$Mass=density\times Volume$

$m=d\times V=1.107 g/ml\times 431.3 mL=477.4491 g$

Mass of calcium chloride = x

w% = 12.0%

$\frac{x}{M}\times 100=12\%$

$x=12\times \frac{M}{100}=12\times \frac{477.4491 g}{100}=57.29 g$

57.29 grams is the mass of calcium chloride in 431.3 mL of a 12.0 wt% solution.

c) Moles of calcium chloride = $\frac{57.99 g}{111 g/mol}=0.5161 mol$

$Molarity(M)=\frac{moles(n)}{V(L)}$

V = Volume of the solution in Liters

n = 0.5161 mole

V = 431.3 mL = 0.4313 L

$M=\frac{0.5161 mol}{0.4313 L}=1.1967 mol/L$

1.1967 mol/L is the formal concentration of calcium chloride in 431.3 mL solution.

6 0

3 years ago

A 5.0 gram sample of lead and a 3.2 gram sample of iron are placed into 367 mL of water. What will be the new volume level of wa

blsea [12.9K]

367.8 mL The density of both lead and iron is greater than the density of water, so they'll both sink. When they sink, the volume of the water plus metals will increase by the volume of the metals. So let's see what those volumes are. Lead has a density of 11.34 g/cm3 Since we have 5.0 grams of lead, the volume will be 5.0 g / 11.34 g/cm3 = 0.440917 cm3 Iron has a density of 7.87 g/cm3 Since we have 3.2 grams of iron, the volume will be 3.2 g / 7.87 g/cm3 = 0.406607 cm3 The total volume will be the sum of the volumes of water, lead, and iron. Giving 367 cm3 + 0.440917 cm3 + 0.406607 cm3 = 367.8475 cm3 Rounding to tenths gives 367.8 cm3 or 367.8 mL

7 0

3 years ago

Please help me with this science question! im confused... Brainliest, thanks, rattings, etc.

MatroZZZ [7]

Answer:

6 km/h west

Explanation:

During part c of the hike, the hiker moved 6 km west, and the time was 9.45 am to 10.45 am.

So, we have:

- displacement: d = 6 km west

- time taken: from 9.45 am to 10.45 am = 1 hour

Therefore, the average velocity is given by the ratio between displacement and time taken:

v = distance/time = 6km/1hr = 6km/h

7 0

4 years ago

Of the reactions involved in the photodecomposition of ozone (shown below), which are photochemical? 1. o2 (g) + hν → o (g) + o

Taya2010 [7]

Answer:

The answers are...

Explanation:

2 and 4.

8 0

3 years ago