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Wittaler [7]
3 years ago
13

The three most common phases of matter are

Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
7 0

Answer:

SOLID, LIQUID, AND GAS

Explanation:

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What is the mass of 0.80 moles of Mg? (1 point)
Aneli [31]

Answer:

m = 19 grams

Explanation:

Given that,

No. of moles, n = 0.8

The molar mass of magnesium, M = 24.305 u

We need to find the mass of 0.80 moles of Mg. We know that given mass to the molar mass is equal to no of moles. Let the mass is m. So,

n=\dfrac{m}{M}\\\\m=n\times M\\\\m=0.8\times 24.305 \\\\m=19.444\ \text{grams}

or

m = 19 grams

So, the mass of 0.8 moles of Mg is 19 grams.

6 0
3 years ago
A major computer chip manufacturer has lost its supplier of silicon. Silicon is widely used in the semiconductor industry becaus
-BARSIC- [3]
We know, silicon is a natural semi-conductor, if manufacturer has lost its supplier then they can look for another element which is quite similar to silicon in electronic configuration. 
We should go down the group, next element in 14th group is "Germanium" so we can use that for that purpose.

In short, Your Answer would be "Germanium"

Hope this helps!
6 0
3 years ago
How do you know if a compound is neutral?
belka [17]
When the overall charge is equal to zero
3 0
4 years ago
Propane burns in air to form water vapor and another gas. What is the volume of the water vapor at 500°C and 1 atm?​
kakasveta [241]

Answer:

253.85 L

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

C₃H₈ + 5O₂ —> 3CO₂ + 4H₂O

From the balanced equation above, 4 moles of water vapor were produced.

Finally, we shall determine the volume of the water vapor produced as follow:

Mole water vapor (n) = 4 moles

Pressure (P) = 1 atm

Temperature (T) = 500 °C = 500 °C + 273 = 773 K

Gas constant (R) = 0.821 atm.L/Kmol

Volume (V) =?

PV = nRT

1 × V = 4 ×0.0821 × 773

V = 253.85 L

Thus, the volume of water vapor obtained is 253.85 L

7 0
3 years ago
1. Based on the observed performance of the air bag models and the amounts of sodium bicarbonate and acetic acid (vinegar) neede
Ira Lisetskai [31]

Sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags since the require more mass and produce less gas.

<h3>Which is the better chemical for an airbag?</h3>

The chemical equation for the production of nitrogen gas from sodium azide is given below:

  • NaN₃ → 2 Na + 3 N₂

1 mole or 66 go of sodium azide produces 3 moles or 67.2 L of nitrogen gas.

The equation for the production of carbon dioxide from sodium bicarbonate and acetic acid is given below:

  • Na₂CO₃ + CH₃COOH → CH₃COONa + CO₂ + H₂O

1 mole, 106 g of Na₂CO₃ and 1 mole, 82 g of CH₃COOH are required to produce 1 mole or 22.4 L of CO₂.

The mass of sodium azide required is less than that of sodium bicarbonate and acetic acid required. Also, sodium azide produces a greater volume of gas. Therefore, sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags.

In conclusion, sodium azide is a better choice in airbags.

Learn more about airbags at: brainly.com/question/14954949

#SPJ1

7 0
2 years ago
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