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anastassius [24]
3 years ago
15

A 12.0 wt% solution of CaCl2 (110.98 g/mol) has a density of 1.107 g/mL.

Chemistry
1 answer:
mariarad [96]3 years ago
6 0

Answer:

a) Mass of solution is 16,605 milli grams.

b) 57.29 grams is the mass of calcium chloride in 431.3 mL of a 12.0 wt% solution.

c) 1.1967 mol/L is the formal concentration of calcium chloride in 431.3 mL solution.

Explanation:

Mass by mass percentage of calcium chloride solution, wt% = 12.0%

Density of the solution = d = 1.107 g/mL

a) Volume of the solution , V= 15.0 mL

Mass of the solution = m

Mass=density\times Volume

m=d\times V=1.107 g/ml\times 15.0 mL=16.605 g

Mass of solution = 16.605 g = 16,605 mg (1g = 1000 mg)

b) Mass of the solution = m

Volume of the solution = V = 431.3 mL

Mass=density\times Volume

m=d\times V=1.107 g/ml\times 431.3 mL=477.4491 g

Mass of calcium chloride = x

w% = 12.0%

\frac{x}{M}\times 100=12\%

x=12\times \frac{M}{100}=12\times \frac{477.4491 g}{100}=57.29 g

57.29 grams is the mass of calcium chloride in 431.3 mL of a 12.0 wt% solution.

c) Moles of calcium chloride = \frac{57.99 g}{111 g/mol}=0.5161 mol

Molarity(M)=\frac{moles(n)}{V(L)}

V = Volume of the solution in Liters

n = 0.5161 mole

V = 431.3 mL = 0.4313 L

M=\frac{0.5161 mol}{0.4313 L}=1.1967 mol/L

1.1967 mol/L is the formal concentration of calcium chloride in 431.3 mL solution.

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