Answer:
0.100 M AlCl₃
Explanation:
The variation of boiling point by the addition of a nonvolatile solute is called ebullioscopy, and the temperature variation is calculated by:
ΔT = W.i
Where W = nsolute/msolvent, and i is the Van't Hoff factor. Because all the substances have the same molarity, n is equal for all of them.
i = final particles/initial particles
C₆H₁₂O₆ don't dissociate, so final particles = initial particles => i = 1;
AlCl₃ dissociates at Al⁺³ and 3Cl⁻, so has 4 final particles and 1 initial particle, i = 4/1 = 4;
NaCl dissociates at Na⁺ and Cl⁻ so has 2 final particles and 1 initial particle, i = 2/1 = 2;
MgCl₂ dissociates at Mg⁺² and 2Cl⁻, so has 3 final particles and 1 initial particle, i = 3/1 = 3.
So, the solution with AlCl₃ will have the highest ΔT, and because of that the highest boiling point.
From the calculations and by the use of Boyles law, the new pressure of the gas is 1.7 atm
<h3>What are gas laws?</h3>
The term gas law is used to demonstrate the relationship between the volume, pressure, number of moles and temperature of a gas.
Using the Boyles law;
P1 = 1 atm
P2 = ?
V1 = 6 L
V2 = 3.5 L
P1V1= P2V2
P2= P1V1/V2
P2= 1 atm * 6 L/3.5 L
= 1.7 atm
Learn more about Boyles law:brainly.com/question/1437490
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Hi! Chemistry is complicated, right?
A hydroxyl group is a group that consists of
oxygen and hydrogen bonds. When they combine, ethanol may be released.
I hope I helped!
Answer:
4 moles, 160 g
Explanation:
The formula for the calculation of moles is shown below:

For
:-
Mass of
= 196 g
Molar mass of
= 98 g/mol
The formula for the calculation of moles is shown below:

Thus,


According to the given reaction:

1 mole of sulfuric acid reacts with 2 moles of NaOH
So,
2 moles of sulfuric acid reacts with 2*2 moles of NaOH
Moles of NaOH must react = 4 moles
Molar mass of NaOH = 40 g/mol
<u>Mass = Moles*molar mass =
= 160 g</u>