A woodworker is making picture frames for some rather large paintings for a local art gallery. Each of the paintings has an area
1 answer:
You might be interested in
Yes. Substitute 2 for x.
We have
We have
In the parallelogram ABCD, join BD.
Consider the triangle Δ ABD.
It is given that AB > AD.
Since, in a triangle, angle opposite to longer side is larger, we have,
∠ ADB > ∠ ABD. --- (1)
Also, AB || DC and BD is a transversal.
Therefore,
∠ ABD = ∠ BDC
Substitute in (1), we get,
∠ ADB > ∠ BDC.
