First of all, you need to know what a 'solution' is, so you'll know it
when you see it.
A 'solution' to an equation is a number, or a set of numbers, that
you can write in place of the variables (the letters), and when you
do that, the equation will have only numbers in it, and it'll be a true
statement.
Your equation has two variables in it ... 'x' and 'y' . In order to find
just a single set of numbers for what both of them must be, you
would need two equations.
The way it stands now, with only one equation, there are actually
an infinite number of solutions. Each solution is a pair of numbers ...
one for 'x' and one for 'y' ... and if you write them into the equation
in place of 'x' and 'y', then the equation is a true statement.
I'll show you how to tell if a pair of numbers is a solution or not.
Here's what that looks like:
Say I give you two pairs of numbers, and I tell you that both of them
are solutions to your equation. The 'solutions' I give you are
x=0
y=1
and
x=2
y=3 .
You don't trust me, and you say to me "Wait just a minute there, dude !
Not so fast. I'll need to check them out and see if those are really solutions
to my equation."
You take the first pair and write it into your equation:
x=1, y=0
9x - 7y = -7
9(0) - 7(1) = -7
0 - 7 = -7
-7 = -7
OK. That's a true statement.
So x=0, y=1 is a solution.
Now check the other one I gave you:
x=2, y=3
9x - 7y = -7
9(2) - 7(3) = -7
18 - 21 = -7
-3 = -7
This is NOT a true statement.
So x=2, y=3 is NOT a solution to your equation.
I pulled a fast one on you. If I was charging you money for solutions,
then you would not pay me for this one, because it's not a solution.
Trick question. There is not one. Due to the fact that 3 is a factor of 15 and if you factor it you will get five which is a third of 15.
Answer:
Question 13: is Side-Side-Angel
Question 14: laws sines.
Question 15: is 1 (which b.)
there my brother tried his best, have a great day TwT
4/6
= (4/2) / (6/2)
= 2/3
6/12
= (6/6) / (12/6)
= 1/2
Because 2/3 ≠ 1/2, 4/6 and 6/12 are NOT equivalent.
