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grandymaker [24]
3 years ago
5

4. Find the area of the given figure. 20 cm 10 cm 3 cm 14 cm 15 cm 13 cm

Mathematics
1 answer:
Talja [164]3 years ago
4 0

I’m sorry I can’t help you without a picture if you could add a picture please I can answer this for you ツ message me back when you do!

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BRAILEST + THANKS <br> F(x)=x^2+14 and g(x)=x−8<br> Find (f+g)(−1)
Murrr4er [49]

Answer:

Step-by-step explanation:

Disclaimer all solutions need to be verified by the student for accuracy in typos, algebra and calculations.

f(x) = x² + 14      g(x) = x - 2      -1 ?   I think it means evaluate when x = -1

Find (f(x) + g(x))  when x = -1

 (f(x) + g(x))  =   [ ( x² + 14)  +  (x - 2)]        insert f(x)  and g(x)

                    =   [ x² + x + 14 - 2]               add like the term

 (f(x) + g(x))  =   x² + x + 12

(f(-1) + g(-1))  =   (-1)² + (-1) + 12             evaluate at x = -1

                   =    1 - 1 + 12

                   =    12

6 0
2 years ago
The chances of a tax return being audited are about 21 in 1 comma 000 if an income is less than​ $100,000 and 29 in 1 comma 000
vladimir2022 [97]

Answer:

a) p=0.021

b) p=0.029

c) Exactly one audit: P=0.0965

More than one audit: P=0.0042

Step-by-step explanation:

a) If the income is less than $100,000, there is a probability of 21 in 1,000 of being audited. This is:

p_1=\dfrac{21}{1,000}=0.021

If the income is equal or more than $100,000, there is a probability of 29 in 1,000 of being audited. This is:

p_2=\dfrac{29}{1,000}=0.029

b) If we have 5 taxpayers with incomes under $100,000, and we want to know the probability that exactly one will be audited, we can model this a binomial randome variable, with p=0.021 and n=5:

P(x=1) = \dbinom{5}{1} p^{1}q^{4}=5*0.021*0.9186=0.0965\\\\

There is a probability of 0.0965 that exactly one out of a sample of five taxpayers with incomes under $100,000 will be audited.

To calculate the probability that more than one will be audited, we use the same distribution:

P(x>1)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0) = \dbinom{5}{0} p^{0}q^{5}=1*1*0.8993=0.8993\\\\\\P(x=1) = \dbinom{5}{1} p^{1}q^{4}=5*0.021*0.9186=0.0965\\\\\\P(x>1)=1-[P(x=0)+P(x=1)]\\\\P(x>1)=1-(0.8993+0.0965)\\\\P(x>1)=1-0.9958\\\\P(x>1)=0.0042

There is a probability of 0.0042 that more than one out of a sample of five taxpayers with incomes under $100,000 will be audited.

8 0
2 years ago
Please answer #’s 6-10
mr_godi [17]

Answer:

6-10 equals -3

Step-by-step explanation:

4 0
2 years ago
Using the data: 2, 2, 3, 3, 3, 4, 5, 6, 6, 19<br><br> What is Q1 and Q3
Anettt [7]

Answer:

Q_1=2

Q_3=6

Step-by-step explanation:

Notice that we already have the data sorted from least to greatest.

Now to find Q1 and Q3 we can use the following formulas

For a set of data ordered from least to greatest of the form X_1, X_2, ..., X_n

Where n is the total number of data

Q_1=X_{\frac{1}{4}(n+1)}

In this case n=10

So:

Q_1=X_{\frac{1}{4}(10+1)}

Q_1=X_{2.75}

Round the nearest whole and get:

Q_1=X_{3}

Q_1=3

For Q3 we have:

Q_3=X_{\frac{3}{4}(n+1)}

Q_3=X_{\frac{3}{4}(10+1)}

Q_3=X_{8.25}

Round the nearest whole and get:

Q_3=X_{8}

Q_3=6

6 0
3 years ago
What is the image point of (6,-4) after a translation left 4 units and down 5 units ?
Evgesh-ka [11]

Answer:

(2,-9)

Step-by-step explanation:

4 0
3 years ago
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