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natima [27]
3 years ago
15

ABCD is a parallelogram. AB>AD. Prove: m∠ADB>m∠BDC. Show your work (statement reason maybe?)

Mathematics
2 answers:
Gwar [14]3 years ago
7 0

In the parallelogram ABCD, join BD.

Consider the triangle Δ ABD.

It is given that AB > AD.

Since, in a triangle, angle opposite to longer side is larger, we have,

∠ ADB > ∠ ABD. --- (1)

Also, AB || DC and BD is a transversal.

Therefore,

∠ ABD = ∠ BDC

Substitute in (1), we get,

∠ ADB > ∠ BDC.

prisoha [69]3 years ago
4 0

Answer:

Step-by-step explanation:

Given that ABCD is a parallelogram and AB >AD

To prove that m∠ADB>m∠BDC.

let us join BD.

Consider triangle ABD.  AB and AD are two sides that AB>AD

By triangle theorem we get

m∠ADB>m∠ABD.

Since opposite sides are parallel, we find that AB and Dc are parallel lines with BD as transversal.

Hence m∠ABD=m∠BDC.(alternate angles)

It follow that

m∠ADB>m∠BDC.

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If AB=BC,AB=4=4x-2,andBC=3x+3,fine the length of AB
laila [671]

Answer:

18

Step-by-step explanation:

First, I'm assuming AB=4=4x-2 was a typo and it's supposed to be AB = 4x - 2

AB=BC

AB = 4x - 2 BC = 3x + 3

4x - 2 = 3x + 3

Solve for x Add 2 to each side

4x - 2 = 3x + 3

4x - 2 + 2 = 3x + 3 + 2

4x = 3x + 5 Subtract 3x from each side.

4x - 3x = 3x- 3x + 5

4x - 3x = 5

x = 5

Now plug back in to the original equations

AB = 4x - 2                  BC = 3x + 3

AB = 4 (5) - 2               BC = 3(5) + 3

AB = 20 - 2                  BC = 15 + 3

AB = 18                        BC = 18

So AB is 18

3 0
3 years ago
A team of three students are working on a language-learning app; they need to develop 300 micro-lessons and 300 micro-tests befo
Olegator [25]

Answer: a) 15 b)

Step-by-step explanation:

Let X be the number of days:

a)

For LESSONS:

Jordan does 10 / day ( 10*X)

Marco 5 / day ( 5*X)

Junyi 5 / day ( 5*X)

For TESTS:

Jordan does 5 / day ( 5*X)

Marco 10 / day ( 10*X)

Junyi 8 / day ( 8*X)

for each they need a total of 300

a) 10X+5X+5X=300 => 20X = 300 => X = 15 days for the lessons

b) 5X+10X+8X = 300 => 23X = 300 => X = 13.04 days for the tests

so they need 15 days to finish both tasks

now if Junyi gets sick we just eliminate his contribution

a) 10X+5X=300 => 15X = 300 => X = 20 days for the lessons

b) 5X+10X = 300 => 15X = 300 => X = 20 days for the tests

so in 20 days they will finish without him

If jordan works 10 hours a day, we just replace him with 10/24

a) 10(10/24)+5X+5X= 300 => X = 29.58 days for the lessons

b) 5(10/24)+10X+8X = 300 => X = 16.51 days for the tests

so at the end to complete both tasks they need 29.58 days

4 0
3 years ago
Find the surface area of the solid below. Round to the nearest tenth it needed. Please someone helpppp
adoni [48]

your answer will be 1275 yd^2

Step-by-step explanation:

hope it helps

3 0
2 years ago
The coordinates of three vertices of a rectangle are -2, 3, -2, -1, and 3, -1. what are the coordinates of the fourth vertex
Lera25 [3.4K]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Q. A room measure 3m 55cm by 2m 25 cm. What is the perimeter of the room?
Bond [772]

Answer:

100cm = 1m

Thus, one more step should be added to your working to arrive at the final answer:

Perimeter

= 10m 160cm

= 11m 60cm

This is because 160cm= 100cm +60cm, which is also equivalent to 1m 60cm.

Alternative working:

Convert all the units to cm first.

\boxed{1 \: m= 100 \: cm}

Length

= 5m 55cm

= 300cm +55cm

= 355cm

Breadth

= 2m 25cm

= 200cm +25cm

= 225cm

Perimeter

= 2(length +breadth)

= 2(355 cm +225 cm)

= 2(580 cm)

= 1160 cm

= 11m 60cm

From the second last step to the last step, you could divide 1160 by 100 to find how many meters are there. You would get a quotient of 11 and a remainder of 60. Since this 60 cannot be changed into meters as a whole number, we can leave it as 11m 60cm. Otherwise, it is also correct to leave it as 1160cm or 11.6m unless otherwise stated.

However, 10m 160cm is not preferred since the conversion of cm to m is done partially, as the 160 cm can still be further simplified.

8 0
2 years ago
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