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Lina20 [59]
3 years ago
15

A^-5b^-4/a^-13b^8 a. a^8 b^12 b. ab^5 c. a^8/b^12 d.b^-9/b^-5

Mathematics
1 answer:
lord [1]3 years ago
5 0
If you would like to solve a^(-5)b^(-4) / a^(-13)b^8,  you can do this using the following steps:

a^(-5)b^(-4) / a^(-13)b^8 = a^13 / a^5b^4b^8 = a^8 / b^12

The correct result would be c. a^8 / b^12.
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The answer is < because 431,511 is more than 413,115

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A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station. Find the ra
Anika [276]

Answer:

The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

Step-by-step explanation:

Given information:

A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.

z=1

\frac{dx}{dt}=430

We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.

y=2

According to Pythagoras

hypotenuse^2=base^2+perpendicular^2

y^2=x^2+1^2

y^2=x^2+1               .... (1)

Put z=1 and y=2, to find the value of x.

2^2=x^2+1^2

4=x^2+1

4-1=x^2

3=x^2

Taking square root both sides.

\sqrt{3}=x

Differentiate equation (1) with respect to t.

2y\frac{dy}{dt}=2x\frac{dx}{dt}+0

Divide both sides by 2.

y\frac{dy}{dt}=x\frac{dx}{dt}

Put x=\sqrt{3}, y=2, \frac{dx}{dt}=430 in the above equation.

2\frac{dy}{dt}=\sqrt{3}(430)

Divide both sides by 2.

\frac{dy}{dt}=\frac{\sqrt{3}(430)}{2}

\frac{dy}{dt}=372.390923627

\frac{dy}{dt}\approx 372

Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

6 0
3 years ago
Does anyone know the answer?
azamat

Answer:

1=163 degrees

2=×=10 degrees

3=×=3

Step-by-step explanation:

54x+1+9x-10=180 we are using this expression because alternate angles add up to 180 degrees

54x+9x+1-10=180

63x-9=180

63×=180+9

63×=189

63×÷63×=189÷63×

X=3

Angle in bold print is (54x+1)

54×3=162

162+1=163 degrees

No.2 Find x

7x+35+x+65 =180

7x+x+35×65=180

8x+100=180

8x=180-100

8x=80

8x÷8x=80÷8

X=10 degrees

No.3 Find x

54x+1+9x-10=180

54x+9x+1-10=180

63x-9=180

63x=180+9

63x=189

63x÷63x=189÷63

X=3

I hope I was of help

6 0
3 years ago
F(3)= 5x^2 - 4x + 9<br> evaluate this quadratic function
Neporo4naja [7]

Answer:

f(3) = 38

Step-by-step explanation:

Given the quadratic function

f\left(x\right)=\:5x^2\:-\:4x\:+\:9

Evaluating the quadratic function

f\left(x\right)=\:5x^2\:-\:4x\:+\:9

substitute x = 3

f\left(3\right)=\:5\left(3\right)^2\:-\:4\left(4\right)\:+\:9

f(3) = 45-16+9

f(3) = 38

Therefore,

  • f(3) = 38
6 0
2 years ago
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