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4 years ago

PLEASE HELPPPP ! 16^x=64^x+4

Mathematics

1 answer:

Vladimir [108]4 years ago

4 0

Answer:

x = -12

Step-by-step explanation:

Set logs up on both sides-

log 16^x = log 64^x+4

The variable goes behind because of the exponent log <em>property</em> (exponents are permitted to go behind the log to multiply)-

x * log 16 = x + 4 * log 64

Divide both logs out-

log 64/log 16 = 1.5

Simplify-

x = x+4(1.5)

1.5x + 6 = x

Remove 1.5-

1 - 1.5 = -.5x

Simplify-

-.5x = 6

Divide both sides-

6/-.5x = -12

Hence, the answer would be -12

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Help quick PLEASE FFTKUKUDIKSSK

valentinak56 [21]

4x-4>20

Step 1: Add four to both sides
4x-4+4>20+4
4x>24
Step 2: Divide both sides by 4
4x divided by 4 and 24 divided by 4
Answer: x>6
Kahal accidentally subtracted instead of adding. He made a mistake in step 2.

3 0

3 years ago

Read 2 more answers

If p is the midpoint of line xy, xp=11-6b and py=6-b, find xp

MariettaO [177]

Since p is the midpoint then xp and pay must equal each other
So, 11-6b=6-b
Solve for b
11-6b=6-b
-6 -6
5-6b=-b
+6b +6b
5=5b
b=1

xp=11-6(1)
xp=5

5 0

3 years ago

Helen purchased 3 copies of a book online at a 20% discount. She also paid $10 for shipping that was not discounted. How much wa

umka21 [38]

Answer:

The original price of the book was $12.50

Step-by-step explanation:

3x - 0.2(3x) + 10 = 40
30x - 2(3x) + 100 = 400
30x - 6x + 100 = 400
24x + 100 = 400
24x = 300
x = 12.50

3 0

2 years ago

The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding

melamori03 [73]

Answer:

We conclude that the mean wedding cost is less than $30,000 as advertised.

Step-by-step explanation:

We are given the following data set:(in thousands)

29100, 28500, 28800, 29400, 29800, 29800, 30100, 30600

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{236100}{8} = 29512.5$

Sum of squares of differences = 3408750

$S.D = \sqrt{\frac{3408750}{7}} = 697.82$

Population mean, μ = $30,000

Sample mean, $\bar{x}$ = $29512.5

Sample size, n = 8

Alpha, α = 0.05

Sample standard deviation, s = $ 697.82

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars}$ We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{29512.5 - 30000}{\frac{697.82}{\sqrt{8}} } = -1.975$

Now,

$t_{critical} \text{ at 0.05 level of significance, 7 degree of freedom } = -1.894$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and reject it.

We conclude that the mean wedding cost is less than $30,000 as advertised.

8 0

4 years ago

-5

Iteru [2.4K]

Answer:

Step-by-step explanation:

4 0

3 years ago