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Oduvanchick [21]
3 years ago
13

After driving 152 ​km, 4/5 of a trip is completed. How long is the total​ trip? How many more kilometers must be driven to compl

ete the​ trip?
Mathematics
2 answers:
MAVERICK [17]3 years ago
8 0

<u>Answer:</u>

The trip is 190 kilometers long and 38 more kilometers must be driven to complete the trip.

<u>Step-by-step explanation:</u>

We are given that after driving 152 ​km, 4/5 of a trip is completed and we are to find how long is the total trip and find out how many more kilometers must be driven to complete the​ trip.

Assuming x to be the total kilometer of the trip:

Total kilometers of the trip = \frac{4}{5} × x=152

x=\frac{152*5}{4} = 190 kilometers

So, 190 - 152 = 38 more kilometers must be driven to complete the​ trip.

nikitadnepr [17]3 years ago
7 0

Answer:

1. Total Trip Distance = 190 kilometers

2. To complete the trip, 38 more kilometers left


Step-by-step explanation:

1.

Let total trip be x kilometers.

So we can say

<em>"152 is \frac{4}{5} of total" --- this into equation is:</em>

152=\frac{4}{5}x\\x=\frac{152}{\frac{4}{5}}\\x=190


Total trip is 190 km.


2.

Since already driven 152, to complete 190, you have to drive  190-152=38 kilometers more.

So, 38 more kilometers to complete the trip.

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You have two unknown rates, so we need to develop two equations to solve for these unknowns (based on the information given on the problem statement):

5x + 10y = 725
x + y = 100

By substitution, we get:

5x + 10(100 - x) = 725
5x + 1000 - 10x = 725
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-5x = -275
x = -275/-5 = 55

100 - 55 = 45

Thus:
The mechanic who worked for 5 hours charged his time at $55/hr, and the mechanic who worked for 10 hours charged his time at $45/hr.

To verify, plug and chug the results back into the original equations:

5(55) + 10(45) = 725
275 + 450 = 725
725 = 725 [OK]

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4 0
3 years ago
Maths!
Ber [7]

Answer:

(1) Variance = 4.5 and Standard deviation = 2.121.

(2) Variance = 4.5 and Standard deviation = 2.121.

(3) The effect on the measure of dispersion if each value is changed uniformly ​is that it remains unchanged.

Step-by-step explanation:

We are given with the following set of data below;

              X                     X-\bar X                   (X-\bar X)^{2}

              5                   5 - 8 = -3                     9

              5                   5 - 8 = -3                     9

              8                   8 - 8 = 0                      0

             10                  10 - 8 = 2                     4

             10                  10 - 8 = 2                     4

             10                  10 - 8 = 2                     4

              9                   9 - 8 = 1                       1

              9                   9 - 8 = 1                       1

         <u>     6     </u>              6 - 8 = -2             <u>        4       </u>          

Total <u>    72     </u>                                         <u>       36       </u>

<u>Firstly, the mean of the above data is given by;</u>

              Mean, \bar X  =  \frac{\sum X}{n}

                              =  \frac{72}{9}  = 8

(1)Now, the variance of the given data is;

            Variance  =  \frac{\sum (X-\bar X)^{2} }{n-1}

                                  =  \frac{36}{9-1}  = 4.5

So, the standard deviation, (S.D.)  =  \sqrt{\text{Variance}}

                                                        =  \sqrt{4.5} = 2.12

(2) Now, each value is added by 2; so the new data set is given by;

              X                     X-\bar X                   (X-\bar X)^{2}

              7                   7 - 10 = -3                     9

              7                   7 - 10 = -3                     9

             10                  10 - 10 = 0                     0

             12                  12 - 10 = 2                     4

             12                  12 - 10 = 2                     4

             12                  12 - 10 = 2                     4

              11                  11 - 10 = 1                       1

              11                  11 - 10 = 1                       1

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<u>Firstly, the mean of the above data is given by;</u>

              Mean, \bar X  =  \frac{\sum X}{n}

                              =  \frac{90}{9}  = 10

(1)Now, the variance of the given data is;

            Variance  =  \frac{\sum (X-\bar X)^{2} }{n-1}

                                  =  \frac{36}{9-1}  = 4.5

So, the new standard deviation, (S.D.)  =  \sqrt{\text{Variance}}

                                                                =  \sqrt{4.5} = 2.12

(3) The effect on the measure of dispersion if each value is changed uniformly ​is that it remains unchanged as we see in the case of variance or standard deviation.

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