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VladimirAG [237]
3 years ago
11

What is the 10th term of the arithmetic sequence defined by the formula

Mathematics
1 answer:
Kisachek [45]3 years ago
8 0

Answer:

4

Step-by-step explanation:

First we should simplify the formula. The simplified formula would be 1/3n+2/3. We then substitute 10 for n. (10/3)+2/3= 12/3=4.

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How much do you earn per week if your annual salary is $40,716?
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783

Step-by-step explanation:

There are 52 weeks in a year. Divide 40,716/52 and you get $783 weekly.

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Mr Changalls garden covers 2/5 of an acre of land .He divides the land into 4 equal sections .what fraction of an acre is each s
kakasveta [241]
1/10.
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so its 1/10
6 0
4 years ago
10x−y = 10<br> −2x+ 5y = −2
Viefleur [7K]

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x=1 & y=0

Step-by-step explanation:

5 0
1 year ago
Use the fundamental identities and appropriate algebraic operations to simplify the following expression. (18 +tan x) (18-tan x)
andrezito [222]

Answer:

a) \left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)=325

b) The lowest point of y=\cos \left(x\right), 0\leq x\leq 2\pi is when x = \pi

Step-by-step explanation:

a) To simplify the expression \left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right) you must:

Apply Difference of Two Squares Formula: \left(a+b\right)\left(a-b\right)=a^2-b^2

a=18,\:b=\tan \left(x\right)

\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)=18^2-\tan ^2\left(x\right)=324-\tan ^2\left(x\right)

324-\tan ^2\left(x\right)+\sec ^2\left(x\right)

Apply the Pythagorean Identity 1+\tan ^2\left(x\right)=\sec ^2\left(x\right)

From the Pythagorean Identity, we know that 1=-\tan ^2\left(x\right)+\sec ^2\left(x\right)

Therefore,

324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325

b) According with the below graph, the lowest point of y=\cos \left(x\right), 0\leq x\leq 2\pi is when x = \pi

3 0
3 years ago
Can someone please help me with this ​
katovenus [111]
He had 24 pounds of flour in his supply
3 0
3 years ago
Read 2 more answers
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