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3 years ago

7

2 + A + A+ a + 3 what is the answer to the equation

1 answer:

torisob [31]3 years ago

4 0

$2+A+A+a+3=2A+a+5$

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How do u find the answer to this

stepladder [879]

11^0 is 1.
11^2= 121

121/1= 121

Final answer: 121

6 0

3 years ago

Solve the equation (1 + x²)dy +xydx= 0

Tatiana [17]

Answer:

$y=\frac{c}{\sqrt[]{x^2+1} }$

Step-by-step explanation:

(1 + x²)dy +xydx= 0

$(1+x^2)dy=-xydx\\\frac{1}{y}dy=\frac{-x}{x^2+1}dx\\$

Integrate both side

$lny=-\frac{1}{2} ln(x^2+1)+c\\y=\frac{c}{\sqrt[]{x^2+1} }$

7 0

3 years ago

– THE ODDS IN FAVOR OF BORIS PENZED WINNING THE HOT

Bezzdna [24]

The probability that Boris will win the contest is:

P = 0.286

<h3>How to get the probability?</h3>

For some given odds a:b, the probability is just computed as the quotient between a and b, which gives:

P = a/b

In this case, the odds are 2:7, so the probability that Boris will win the contest is:

P = 2/7 = 0.286

Written in percentage form, we get:

P = 28.6%

If you want to learn more about probability:

brainly.com/question/24756209

#SPJ1

6 0

1 year ago

Which choice shows the image of figure 1 being transformed with a translation of 4 units down followed by a rotation of 90° coun

vladimir2022 [97]

Answer:

3rd one? Someone correct me if I’m wrong

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

11 POINTS PLZ HELP EMERGENCY

Bad White [126]

Part A

The given expression is:

$(-5(1+2i)+3i(3-4i)$

We expand to get:

$-5-10i+9i-12i^2$

Note that $i^2=-1$

$12-5-10i+9i$

$-5-10i+9i+12$

$7-i$

Part Bi)

The given expression is;

$\sqrt{-50}$

We simplify to get:

$\sqrt{25\times 2\times -1}$

$\sqrt{25\times} \sqr{2}\times \sqrt{-1}$

Note that:

$\sqrt{-1}=i$

$5\sqr{2}i$

This is now of the form $a+bi$ , where $a=0,b=5\sqr{2}$ .

This explains why it is a complex number;

Part bii)

The given expression is :

$\frac{\sqrt{-50} }{\sqrt{5}}$

We simplify to get

$\sqrt{\frac{-50 }{5}}$

$\sqrt{-25}$

$\sqrt{-25}=\sqrt{25}\times \sqrt{-1}$

$\sqrt{-25}=5\times i$

$\sqrt{-25}=5i$

Part C

We want to simplify:

$i^{22}$

We rewrite in terms of $i^2$

$i^{22}=(i^2)^{11}$

$i^{22}=(-1)^{11}$

$i^{22}=-11$

5 0

3 years ago