Answer:
A
Step-by-step explanation:
this is more of a mind game. Lots of words to throw you off. Daily a cow produces a mean of 6.2 gallons (average of 6.2 gallons, meaning they already found the mean, "averaged" it out for you) with a deviation of .7 gallons ("give or take" .7 gallons). On any given day (throw these words out) 68% of the cows (don't need this information to answer the question either, thrown in to confuse you) will produce an amount of milk within which of the following ranges? Just subtract the deviation ("give or take number") .7 gallons from the mean (average (already determined)) 6.2 gallons which is 5.5 gallons THEN add the deviation ("give or take number") .7 gallons to the mean (average (already determined)) 6.2 gallons which is 6.9 gallons. Your answer is A 5.5 gallons to 6.9 gallons. You don't even have to go crazy on the math on this question you can rule them all out but A immediately with subtracting .7 from 6.2. Mind games .... LOL sneaky.
The answer to the question is D
Grape- 8/20 = 2/5 = 40%
cherry - 7/20 = 35%
lemon - 5/20 = 25%
Answer:
P(O and O) =0.1296
P=0.3778
Step-by-step explanation:
Given that
blood phenotypes in a particular population
A=0.48
B=0.13
AB=0.03
O=0.36
As we know that when A and B both are independent that
P(A and B)= P(A) X P(B)
The probability that both phenotypes O are in independent:
P(O and O)= P(O) X P(O)
P(O and O)= 0.36 X 0.36 =0.1296
P(O and O) =0.1296
The probability that the phenotypes of two randomly selected individuals match:
Here four case are possible
So
P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)
P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36
P=0.3778
