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kondaur [170]
3 years ago
9

For the following relation, find the: a) Reflexive closure b) Symmetric closure c) Transitive closure 2 You may include explanat

ion if you like but no explanation is required. Your solution may be a graphical representation.v g
Mathematics
1 answer:
Luba_88 [7]3 years ago
5 0

Answer:

Following are the complete solution in the attached file.

Step-by-step explanation:

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3 years ago
Tan(A+45°) - tan(A-45°) =2sec2A​
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Answer:

\tan(A + 45 \degree)  -  \tan(A - 45 \degree)  \\   \\  = \frac{ \tan(A)  +  \tan(45 \degree) }{1 -  \tan(A)  \tan(45 \degree) }  -  \frac{ \tan(A)  -  \tan(45 \degree) }{1 +  \tan(A)  \tan(45 \degree) }  \\  \\

but tan 45° is 1;

=  \frac{ \tan(A) }{1 -  \tan(A) }  -  \frac{ \tan(A) }{1 +  \tan(A) }  \\  \\  \frac{\tan(A)  + { \tan }^{3}  A   + \tan(A)  -   { \tan}^{3}  A}{1 - { \tan }^{2} A }  \\  \\  =  (\frac{2  \tan(A) }{1 -  { \tan }^{2} A})  \\   \\  =  \frac{2 \sin(A) }{ \cos(A)  }  \times  { \sec }^{2} A \\  \\  =  \frac{2}{ \cos(2A) }  \\  \\  = 2 \sec(2A)

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3 years ago
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