The perimeter of a rectangle is 256 inches. how long are the sides if the length exceeds the width by 16 inches? mark lets x rep resent the width of the rectangle and writes the equation 2x + 2(x + 16) = 256. solving for x, the width of the rectangle is 56 60 68
2 answers:
Answer:
X=56
Step-by-step explanation:
We have 2x + 2x + 32 = 256; Then 4x + 32 = 256; 4x = 256-32; 4x = 224; x = 224/4; x = 56; The width is 2·56 = 112 inches; The length is 112 + 16 = 128 inches;
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