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kodGreya [7K]
3 years ago
7

The perimeter of a rectangle is 256 inches. how long are the sides if the length exceeds the width by 16 inches? mark lets x rep

resent the width of the rectangle and writes the equation 2x + 2(x + 16) = 256. solving for x, the width of the rectangle is 56 60 68
Mathematics
2 answers:
mr Goodwill [35]3 years ago
5 0

Answer:

X=56

Step-by-step explanation:

Elodia [21]3 years ago
3 0
We have 2x + 2x + 32 = 256;
Then 4x + 32 = 256;
4x = 256-32;
4x = 224;
x = 224/4;
x = 56;
The width is 2·56 = 112 inches;
The length is 112 + 16 = 128 inches;
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Answer:

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Solve for x: x^2+4x-5=16x
BigorU [14]
Solve for x: x^2+4x-5=16x
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6 0
3 years ago
Read 2 more answers
PLEASE ANSWER THIS!! 16 POINTS!<br><br> (2/3)*2 + 1/2
alexira [117]

Answer:

=7/6

Step-by-step explanation:

Join 4/3=1:7/3

7/3/2

Apply the fraction rule:=

7/3x2

Multiply the numbers=

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5 0
3 years ago
Read 2 more answers
(**15 POINTS**)
bonufazy [111]

Answer:

0.6x = 87

Step-by-step explanation:

Hi, to answer this question we have to write en equation:

We have to multiply the variable x by the percentage given (60%) in decimal form (divided by 100). That expression must be equal to 87.

Mathematically speaking:

x (60/100) = 87

0.6x = 87

Feel free to ask for more if needed or if you did not understand something.

8 0
3 years ago
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