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4 years ago

Question: what should you do first to graph the equation? graph the equation.

Mathematics

1 answer:

Sliva [168]4 years ago

7 0

Answer:

Plot a point at the y-intercept.

In your case, you will need to plot 2 (y-intercept) on the graph first.

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Find the value of r 4(x-3)-r+2x=5(3x-7)-9x

vlabodo [156]

r = 4(x-3)/5(3x-7) + 11x

6 0

3 years ago

Use the power series for 1 1−x to find a power series representation of f(x) = ln(1−x). What is the radius of convergence? (Note

Viktor [21]

a. Recall that

$\displaystyle\int\frac{\mathrm dx}{1-x}=-\ln|1-x|+C$

For $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n$

By integrating both sides, we get

$\displaystyle-\ln(1-x)=C+\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}$

If $x=0$ , then

$\displaystyle-\ln1=C+\sum_{n=0}^\infty\frac{0^{n+1}}{n+1}\implies 0=C+0\implies C=0$

so that

$\displaystyle\ln(1-x)=-\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}$

We can shift the index to simplify the sum slightly.

$\displaystyle\ln(1-x)=-\sum_{n=1}^\infty\frac{x^n}n$

b. The power series for $x\ln(1-x)$ can be obtained simply by multiplying both sides of the series above by $x$ .

$\displaystyle x\ln(1-x)=-\sum_{n=1}^\infty\frac{x^{n+1}}n$

c. We have

$\ln2=-\dfrac\ln12=-\ln\left(1-\dfrac12\right)$

$\displaystyle\implies\ln2=\sum_{n=1}^\infty\frac1{n2^n}$

4 0

3 years ago

How can a diagram help you know the exact answer

ASHA 777 [7]

What type of diagram?

6 0

4 years ago

10 pts

aliya0001 [1]

Circumference = pi * diameter
diameter = 8.5; pi = 3.14

C = 3.14 * 8.5
C = 26.69 in = 26.7 in

3 0

3 years ago

Estimate the sum of 299 and 388

Svetllana [295]

For this case we have the following numbers:

299

388

Let's round up each of the numbers to the nearest hundred,

We have then:

299 = 300

388 = 400

We note that now we have two numbers whose approximation is easier to add.

We have then:

300 + 400 = 700

Answer:

The sum of 299 + 388 is approximately:

700

7 0

4 years ago

Read 2 more answers