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polet [3.4K]
2 years ago
14

Pls Help I give brainlyest

Mathematics
2 answers:
Alecsey [184]2 years ago
6 0

Answer:

increased by 10%

Step-by-step explanation:

Misha Larkins [42]2 years ago
4 0
The very top line in increased by 10%
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-3(4s-1)-3=-3(6s+6)-3
OlgaM077 [116]

Answer:

I think its 6 not sure

Step-by-step explanation:

5 0
2 years ago
What is the solution to this equation? <br> log_7 (5 + 11x) = 2
11111nata11111 [884]

Answer:

x = 4

Step-by-step explanation:

Using the rule of logarithms

log_{b} x = n , then x = b^{n}

Given

log_{7} (5 + 11x) = 2 , then

5 + 11x = 7² = 49 ( subtract 5 from both sides )

11x = 44 ( divide both sides by 11 )

x = 4

5 0
2 years ago
102/159 = x/4<br><br> Find X
-BARSIC- [3]
102/159 = x/4
34/53 = x/4
34(4) = x(53)
136 = 53x
136/53 = x
5 0
3 years ago
8 grams = milligrams
Digiron [165]

Answer:

8,000 miligrams

Step-by-step explanation:

There's 1000 milligrams in a gram so you would have to do multiplication.

which if you do..

8x1000

you should get...

8000 milligrams

4 0
3 years ago
Read 2 more answers
A laptop producing company also produces laptop batteries, and claims that the batteries
gregori [183]

Answer:

There is enough evidence to support the claim that the batteries power the laptops for significantly less than 4 hours. (P-value = 0).

The null and alternative hypothesis are:

H_0: \mu=4\\\\H_a:\mu< 4

Step-by-step explanation:

<em>The question is incomplete: To test this claim a sample or population standard deviation is needed.</em>

<em>We will estimate that the sample standard deviation is 2 hours, and use a t-test to test that claim.</em>

<em> NOTE (after solving): The difference between the sample mean and the mean of the null hypothesis is big enough to reject the null hypothesis, even when we have a sample standard deviation of 3.5 hours, which can be considered bigger than the maximum standard deviation for the sample.</em>

This is a hypothesis test for the population mean.

The claim is that the batteries power the laptops for significantly less than 4 hours.

Then, the null and alternative hypothesis are:

H_0: \mu=4\\\\H_a:\mu< 4

The significance level is 0.05.

The sample has a size n=500.

The sample mean is M=3.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2}{\sqrt{500}}=0.0894

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{3.5-4}{0.0894}=\dfrac{-0.5}{0.0894}=-5.5902

The degrees of freedom for this sample size are:

df=n-1=500-1=499

This test is a left-tailed test, with 499 degrees of freedom and t=-5.5902, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the batteries power the laptops for significantly less than 4 hours.

5 0
3 years ago
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