14+m=56
m=56-14(minus 56 from both side)
M=42
The angle between the planes is the same as the angle between their normal vectors, which are
<em>n</em><em>₁</em> = ⟨1, 1, 1⟩
<em>n</em><em>₂</em> = ⟨4, 3, 1⟩
The angle <em>θ</em> between the vectors is such that
⟨1, 1, 1⟩ • ⟨4, 3, 1⟩ = ||⟨1, 1, 1⟩|| ||⟨4, 3, 1⟩|| cos(<em>θ</em>)
Solve for cos(<em>θ</em>) :
4 + 3 + 1 = √(1² + 1² + 1²) √(4² + 3² + 1²) cos(<em>θ</em>)
8 = √3 √26 cos(<em>θ</em>)
cos(<em>θ</em>) = 8/√78
Answer:
x = 4
Step-by-step explanation:
First you need to multiply both sides of the equation by -6/5
-6/5 × (-5/6x) = -6/5 × -10/3
Then you need to calculate and reduce. First, you'll reduce the numbers with the greatest common divisor, 6.
1/5 × 5x = -6/5 × (-10/3)
then reduce the greatest common divisor, 5
x = -6/5 × (-10/3)
Then multiply (multiplying two negatives equals a positive)
x = 6/5 × 10/3
reduce the greatest common divisor, 3
x = 2/5 × 10
reduce the greatest common divisor, 6
x = 2 × 2
x = 4
(i know this is confusing, sorry)
Answer:
you use older of operations to solve this
