Ask question

Ask question

All categories

3 years ago

15

What is the answer to

ac{v}{8} = 10" alt=" \frac{v}{8} = 10" align="absmiddle" class="latex-formula">

2 answers:

Shkiper50 [21]3 years ago

7 0

Answer:

80

Step-by-step explanation:

$\frac{v}{8} =10\\v=10*8\\v=80$

ira [324]3 years ago

3 0

V/8 = 10
10 * 8 = V
80 = V

So, in conclusion, V is equal to 80.

You might be interested in

URGENT, According to the graph below , the slope of line B is

ra1l [238]

Answer:

the answer is 3/2

Step-by-step explanation:

the formula of the slope is

3 0

2 years ago

Read 2 more answers

A 748-N man stands in the middle of a frozen pond of radius 4.0 m. He is unable to get to the other side because of a lack of fr

Ber [7]

Answer:

The man will take 64 seconds to reach to the south shore of the frozen pond.

Step-by-step explanation:

Given:

Weight of the man = 748 N Mass of the man, $(m)= \frac{W}{g}$ = $\frac{748}{9.8}$ = $76.32$ kg

Radius of the pond $(r)$ = 4 m

Mass of the textbook = 1.2 kg

Velocity at which the textbook is thrown = 4 ms^1

We have to find the velocity of the man after the throw.

Let the velocity is $V_m$ .

Now using law of conservation of momentum we can find the $V_m$ value.

$m_(_b_)V_b_(_i_) +m_(_m_)V_m_(_i_) =m_(_b_)V_b_(_f_)+m_(_m_) V_m_(_f_)$

Considering $V_m_(_f_)=V_m$

And initial velocity of both the man and book i.e $V_b_(_i_)=0,\ V_m_(i_)=0$

So,

⇒ $0 =m_(_b_)V_b_(_f_)+m_(_m_) V_m$

⇒ Plugging the values.

⇒ $V_m=-\frac{m_(_b_)V_b_(_f_)}{m_(_m_)}$

⇒ $V_m=-\frac{1.2\times 4}{76.32}$

⇒ $V_m=-0.062$ ms^-1

Here the negative velocity is meant for opposite direction of the throw.

Numerically we will write, $V_m = 0.062$

With this velocity the man will move towards south.

We have to calculate the time taken by the man to move to its south shore.

And we know $velocity(v)\times time(t) = distance(d)$

Let the time taken be $t$ and $v\times t = d$ and $d=r$ then, $V_m\times t=r$

Then

⇒ $t=\frac{radius\ (r)}{V_m}$

⇒ Plugging the values.

⇒ $t=\frac{4}{0.062}$

⇒ $t =64$ sec

The man will take 64 seconds to reach to the south shore of the frozen pond (circular).

5 0

2 years ago

Karl is making a pot of chili. The recipe calls for 3/8 cup of chili powder, but Karl only wants to use half as much so it won’t

tresset_1 [31]

Answer:

KArl should use 3/16 cups of chili powder

Step-by-step explanation:

Given that:

Recipe's requirement : 3/8 cups

Karl wants to use half : 1/2

The given question involves fractions. When the number of cups has to be divided into half, it will be multiplied with 1/2.

So,

Multiplying the chili powder requirement of the recipe to 1/2

$=\frac{3}{8} * \frac{1}{2}\\= \frac{3}{16}$

Hence,

KArl should use 3/16 cups of chili powder

4 0

3 years ago

Read 2 more answers

Jake has just become the senior marketing rep for a new chain of upscale hotels. His first responsibility is to develop a

cluponka [151]

Answer:

Startup.

Step-by-step explanation:

If Jake has just become the senior marketing rep for a new chain of upscale hotels, his first responsibility is to develop a plan, commonly referred to as the startup.

5 0

3 years ago

The savings account offering which of these APRs and compounding periods offers the best APY?

zzz [600]

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\
$

$\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\
$

$\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1$

7 0

2 years ago

Read 2 more answers