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weqwewe [10]
3 years ago
7

A shop advertised a 27% off sale. If a coat originally sold for 253 , find the decrease in price and the sale price

Mathematics
1 answer:
OverLord2011 [107]3 years ago
8 0
253 * 0.27= 68.31 (discounted price)

253-68.31 OR 253*0.73= 184.69 (sale price)
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Give a set of five integers, two positive and three negative, for which the mean, median, and mode are all -3
koban [17]
That's 5 integers...

Logic tells me that a number divided by 5 should be equal to -3. -15/5 is in fact equal to -3.

Let's find 5 integers (two positive and three negative) when added up together equal -15.

-14, -3, -3, 2, 3.

[(-14)+(-3)+(-3)+2+3]/5 = (-15)/5 = -3

Mean = -3

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Now let's put these numbers in order, from lowest to highest - then pick out the middle value...

-14, -3, [-3], 2, 3

The median turns out to be -3.

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Let's look at the numbers once again...

-14, -3, -3, 2, 3

It turns out that -3 appears the most, therefore -3 is the mode too.
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3 years ago
Evaluate the expression 50g^2 if g = 1/5.
andrezito [222]

Answer:

2

Step-by-step explanation:

50*1/5 squared

1/5 = 0.2.

0.2 squared = 0.04

0.04 * 50 = 2

3 0
3 years ago
Geometry thing help<br>aa
irina [24]

Answer:

Step-by-step explanation:

Since we know that the two lines are parallel because of alternate interior angles (5x-20)=3x

then solve for x

5x-20=3x

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5 0
3 years ago
Read 2 more answers
Clarissa went to her favorite restaurant for dinner. if her meal cost 12.00 and she wants to add a 15 %tip how much is her total
Natalija [7]
12.00*0.15=1.80
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3 0
3 years ago
Read 2 more answers
(60 points)
natka813 [3]

Answer:

<h2>2. D. 64</h2><h2>5. B. 1, -3/2</h2><h2>6. C. 0, 2</h2>

Step-by-step explanation:

2.\\(a-b)^2=a^2-2ab+b^2\\\\x^2-16x=-8\\\\x^2-2(x)(8)=-8\\\\\text{We have}\ 2ab=2(x)(8).\ \text{Therefore}\ b=8.\\\\x^2-2(x)(8)=-8\qquad\text{add}\ 8^2=64\ \text{to both sides}\\\\x^2-2(x)(8)+8^2=-8+64\\\\(x-8)^2=56

5.\\2x^2+x-1=2\qquad\text{subtract 2 from both sides}\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\qquad\text{subtract 3 from both sides}\\2x=-3\qquad\text{divide both sides by 2}\\\boxed{x=-\dfrac{3}{2}}\\\\x-1=0\qquad\text{add 1 to both sides}\\\boxed{x=1}

6.\\2x^2-4x=0\qquad\text{divide both sides by 2}\\\\x^2-2x=0\\\\x(x-2)=0\iff x=0\ \vee\ x-2=0\\\\\boxed{x=0}\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}

8 0
3 years ago
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