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Elenna [48]
3 years ago
9

15. A rectangular wooden gate with two diagonal boards across the front

Mathematics
1 answer:
frez [133]3 years ago
5 0

cute ako☁

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Find the equation of the line, where P is a point on the graph of the line.<br><br> m=2/3 , P(3,5)
Liula [17]

Answer:

The answer is

y =  \frac{2}{3} x + 3

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To write an equation of a line given a point and slope we have

y - y1 = m( x - x1)

where (x1 , y1 ) is the point and m is the slope

Equation of the line using point P(3 , 5) and m = 2/3 is

y - 5 =  \frac{2}{3} (x - 3)

y - 5 =  \frac{2}{3} x - 2

y =  \frac{2}{3} x + 5 - 2

We have the final answer as

y =  \frac{2}{3} x + 3

Hope this helps you

4 0
3 years ago
5 scholars ran a marthon each one ran 1\5 of a mile how far did the students run in all
IrinaK [193]

9514 1404 393

Answer:

  1 mile

Step-by-step explanation:

  5 × (1/5 mi) = 5/5 mi = 1 mi

The students ran 1 mile in all.

3 0
3 years ago
How do you write 8 million, 6 ten-thousan, 3 hundred ,9ones?
erica [24]

8,610,309 should be it

3 0
3 years ago
6x+18=h(3x+9) what value the constant h in the equation shown below will result in a infinite number of solutions
pav-90 [236]
For there to be an infinite number of solutions, the quantity on the left side of the equation must be the same as on the right.
First, distribute the equation to get 
6x + 18 = 3xh + 9h
If h = 2, the equation on the right would also be 6x + 18 which would yield the same equation and hence an infinite number of solutions
So the answer is h = 2
4 0
3 years ago
Read 2 more answers
How many different perfect cubes are among the positive actors of 2021^2021
9966 [12]

Answer:

hope this helps :D

Step-by-step explanation:

Perfect cube factors:

If a number is a perfect cube, then the power of the prime factors should be divisible by 3.

Example 1:Find the number of factors of293655118 that are perfect cube?

Solution: If a number is a perfect cube, then the power of the prime factors should be divisible by 3. Hence perfect cube factors must have

2(0 or 3 or 6or 9)—– 4 factors

3(0 or 3 or 6)  —–  3  factors

5(0 or 3)——- 2 factors

11(0 or 3 or 6 )— 3 factors

Hence, the total number of factors which are perfect cube 4x3x2x3=72

Perfect square and perfect cube

If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.

Example 2: How many factors of 293655118 are both perfect square and perfect cube?

Solution: If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.Hence both perfect square and perfect cube must have

2(0 or 6)—– 2 factors

3(0 or 6) —– 2 factors

5(0)——- 1 factor

11(0 or 6)— 2 factors

Hence total number of such factors are 2x2x1x2=8

Example 3: How many factors of293655118are either perfect squares or perfect cubes but not both?

Solution:

Let A denotes set of numbers, which are perfect squares.

If a number is a perfect square, then the power of the prime factors should be divisible by 2. Hence perfect square factors must have

2(0 or 2 or 4 or 6 or 8)—– 5 factors

3(0 or 2 or 4 or 6)  —– 4 factors

5(0 or 2or 4 )——- 3 factors

11(0 or 2or 4 or6 or 8 )— 5 factors

Hence, the total number of factors which are perfect square i.e. n(A)=5x4x3x5=300

Let B denotes set of numbers, which are perfect cubes

If a number is a perfect cube, then the power of the prime factors should be divisible by 3. Hence perfect cube factors must have

2(0 or 3 or 6or 9)—– 4 factors

3(0 or 3 or 6)  —–  3  factors

5(0 or 3)——- 2 factors

11(0 or 3 or 6 )— 3 factors

Hence, the total number of factors which are perfect cube i.e. n(B)=4x3x2x3=72

If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.Hence both perfect square and perfect cube must have

2(0 or 6)—– 2 factors

3(0 or 6) —– 2 factors

5(0)——- 1 factor

11(0 or 6)— 2 factors

Hence total number of such factors are i.e.n(A∩B)=2x2x1x2=8

We are asked to calculate which are either perfect square or perfect cubes i.e.

n(A U B )= n(A) + n(B) – n(A∩B)

=300+72 – 8

=364

Hence required number of factors is 364.

8 0
3 years ago
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