Answer:
Correct answer is (d) Scalable solution for an enterprise environment
Explanation:
Scaling and enterprise simply means adding up resources to the business need. By adding hardware (s) or by upgrading the existing hardware without changing much of the application, one will be able to implement a three-tier campus network.
Answer:
Written in Python
filenm = input("File name: ")
myfile = open(filenm+".txt")
for i in range(10):
line = myfile.readline()
print(line)
print("End of file")
Explanation:
This line prompts user for file name
filenm = input("File name: ")
This line creates an instance of the file
myfile = open(filenm+".txt")
This line iterates through the 10 lines
for i in range(10):
This line reads the line
line = myfile.readline()
This line prints each line
print(line)
This line prints a message indicating that all possible lines have been printed
print("End of file")
Answer:
THANK YOUUUUU! Please have a great day and rateme10/10 is one of them!
Explanation:
The ipsec component software that handles the tasks of encrypting, authenticating, decrypting, and checking packets is called IKE. It is short for Internet Key Exchange. It is <span>a network security Protocol aimed to allow two devices to actively exchange Encryption Keys and negotiate Security Associations </span>
Answer:
The function in C is as follows:
#include <stdio.h>
int C_ball(int height){
if(height == 1) {
return 1;}
return (height * height) + C_ball(height - 1);}
int main(){
int n;
printf("Height: ");
scanf("%d",&n);
printf("Balls: %d",C_ball(n));
return 0;
}
Explanation:
The function begins here
#include <stdio.h>
This defines the function
int C_ball(int height){
If height is 1, return 1
<em>if(height == 1) {
</em>
<em> return 1;}</em>
This calls the function recursively
return (height * height) + C_ball(height - 1);}
The main begins here
int main(){
This declares the height as integer
int n;
This prompts the user for the height
<em> printf("Height: ");
</em>
<em> scanf("%d",&n);</em>
This calls the function
printf("Balls: %d",C_ball(n));
return 0;
}