Answer:
Total Memory= 4 KB = 4096 bytes = 32768 bits
Explanation:
<em><u>1. Data lines are 8 From D0 to D7</u></em>
so
Total memory at single address locations is 8 bits.
<em><u>2. Address lines are 12 (A0 to A11)</u></em>
There are 12 address lines but 3 out 12 are for selction of chip or memory bank.
so only 9 pins are there to address the locations on one chip.
Total No. of address locations on single chip = 2^9 = 512 locations
as 1 location is 1 byte so total memory of single chip is 512 bytes.
<u><em>3. Total Memory Bank </em></u>
There are total 3 selection pins for memory bank.
so
Total chips = 2^3 = 8.
<em><u>4. Total Memory </u></em>
Total size of 1 chip = 512 bytes
Total size of 8 chip = 8x512 bytes = 4096 bytes = 4096/1024 kb = 4 kb
<em>So total memory of system is 4 Kb = 4096 bytes = 32768 bits</em>
Answer:
B. SSD
Explanation:
VMs or virtual machines are virtually created environment for multiple operating system on a host operating system. The host operating system has an extension called Hyper-V. The hyper-V manager helps to manage the virtual machine's activities.
The VMs can hold applications in their respective containers, which requires a partition of the storage. So when more VMs are configured, more storage memory is required to store their individual data. The VMs in a computer system can share a network interface card.
There two problems related to this problem:
First is the coefficient of static friction between the map
and the crate.
And the second one is at what angle does the crate begin to
slide if the mass is doubled.
1.
To look for the coefficient of static friction:
ΣF = 0
μ x m x g x cos θ = m * g * sin θ
μ = sin θ/ cos θ = tan θ
μ = tan 24 = 0.45
2.
At what angle… the solution is:
The static friction or μ does not depend
on mass, so the angle is still 24.
