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PIT_PIT [208]
3 years ago
14

Which expression is equivalent to sqt 36/25? 6/25 5/6 6/5 36/25

Mathematics
1 answer:
Andru [333]3 years ago
6 0

Answer:

C

Step-by-step explanation:

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Please help!!<br> Will mark brainliest
strojnjashka [21]

Answer:

y = 2

Step-by-step explanation:

y=2 every time you add 3 to x your adding 2 to the y

-3 + 3 = 0 and 3 + 2 = 5

0 + 3 = 3 and 5 + 2 = 7

3 0
3 years ago
The expression 4h−3 factored is
lubasha [3.4K]

Answer:

prime

Step-by-step explanation:

this equation is not factorable

6 0
2 years ago
3+p/2=6 How do I solve this?
Diano4ka-milaya [45]

\boxed{\underline{\bf \: ANSWER}}

\sf\frac { 3 + p } { 2 } = 6 \\

Multiply both sides by 2.

\sf \: 3+p=6\times 2

Multiply 6 and 2 to get 12.

\sf \: 3+p=12

Subtract 3 from both sides.

\sf \: p=12-3

Subtract 3 from 12 to get 9.

\boxed{\bf \: p=9}

____

Hope it helps.

RainbowSalt2222

5 0
3 years ago
In this diagram, BAC~EDF. If the area of BAC=15 in2, what is the area of EDF? 4, 5.
lesya692 [45]

Answer:

9.6 square inches.

Step-by-step explanation:

We are given that ΔBAC is similar to ΔEDF, and that the area of ΔBAC is 15 inches. And we want to determine the area of ΔDEF.

First, find the scale factor <em>k</em> from ΔBAC to ΔDEF:

\displaystyle 5 k = 4

Solve for the scale factor <em>k: </em>

<em />\displaystyle k = \frac{4}{5}<em />

<em />

Recall that to scale areas, we square the scale factor.

In other words, since the scale factor for sides from ΔBAC to ΔDEF is 4/5, the scale factor for its area will be (4/5)² or 16/25.

Hence, the area of ΔEDF is:

\displaystyle \Delta EDF = \frac{16}{25}\left(15\right) = 9.6\text{ in}^2

In conclusion, the area of ΔEDF is 9.6 square inches.

5 0
2 years ago
-5(-6k + 10) =<br> Help ASAP
Fudgin [204]

Answer:

<h2>30k - 50</h2><h2 />

Step-by-step explanation:

-5 (-6k + 10)

= 30k - 50

8 0
3 years ago
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