Given that the two swimmers competed and Ursula's speed is 60 m/min while Andre's speed is 48 m/min. The distance that the Ursula will catch up with Andre will be:
distance=(relative speed)×(time)
relative speed=60-48=12 m/min
the two swimmers met at a distance of:
12×1
=12 meters
Answer:
x=3/7 and x= 3
Step-by-step explanation:
First simplify:
-14 x^2 +48x -18
divide everything by -2
-2(7 x^2 -24x +9) (Multiply the leading coefficient 7 by the constant 9)
-2 (x^2 -24x +63)
-2 [(x-3)(x-21)] Now divide the 7 that you multiplied earlier from 3 and 21
-2 [(x-3/7)(x-21/7)]
-2 [(7x-3)(x-3)]
Hence, the zeroes are 3/7 and 3
Hope this helps!
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The sum of the given expression expressed as a quadratic equation is 10x^2 + 13x + 11
<h3>Sum of expressions</h3>
Expressions are equations separated by mathematical signs. This expressions are known to contains certain unknowns
Given the following expression
10x^2 +7x+6 and 6x + 5
We are to take the sum of both expression to have:
f(x) = 10x^2 +7x+6 + 6x + 5
Collect the like terms
f(x) = 10x^2 + 7x + 6x + 6 + 5
f(x) = 10x^2 + 13x + 11
Hence the sum of the given expression expressed as a quadratic equation is 10x^2 + 13x + 11
Learn more on sum of functions here: brainly.com/question/11602229
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Answer:
Area = 36 
Step-by-step explanation:
There must be an error with the statement, because it is strange that the length of the frame is equal to its thickness.
Assuming that the data supplied is correct, we can do the following procedure.
Let's call L the length of the frame.
We know how much each side of the square measures.
L = 3 inches
We also know that the thickness (s) is:
s = 3 inches.
Then the area of the frame is equal to:
Area = Perimeter * thickness
Area = 4L*s
Area = 3*4*3
Area = 36
