Find all real zeros of tf(x)=x-14x² + 47x-18
1 answer:
Answer:
x=3/7 and x= 3
Step-by-step explanation:
First simplify:
-14 x^2 +48x -18
divide everything by -2
-2(7 x^2 -24x +9) (Multiply the leading coefficient 7 by the constant 9)
-2 (x^2 -24x +63)
-2 [(x-3)(x-21)] Now divide the 7 that you multiplied earlier from 3 and 21
-2 [(x-3/7)(x-21/7)]
-2 [(7x-3)(x-3)]
Hence, the zeroes are 3/7 and 3
Hope this helps!
If you think I helped, Please mark brainliest! Would really appreciate!
You might be interested in
63 I think, you would subtract
Answer:
x = 4
Step-by-step explanation:
1.3x - 10 = 0.8x - 8
Add 10 to both sides.
1.3x = 0.8x + 2
Subtract 0.8x from both sides.
0.5x = 2
Divide by 0.5.
x = 4.
Proof:
1.3x - 10 = 0.8x - 8
1.3(4) - 10 = 0.8(4) - 8
5.2 - 10 = 3.2 - 8
-4.8 = -4.8
Answer:
ten times time
Step-by-step explanation:
ten time ten or ten multiple by ten
give brainliest please I need it to level up
Answer:
d only.
Step-by-step explanation:
lol i know ur map testing, i had the same question yesterday
Answer: 3/5 i think ;-; if its not well then uhhhhh sorry?
Step-by-step explanation:
