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FinnZ [79.3K]
3 years ago
12

Find all real zeros of tf(x)=x-14x² + 47x-18​

Mathematics
1 answer:
BabaBlast [244]3 years ago
4 0

Answer:

x=3/7 and x= 3

Step-by-step explanation:

First simplify:

-14 x^2 +48x -18

divide everything by -2

-2(7 x^2 -24x +9) (Multiply the leading coefficient 7 by the constant 9)

-2 (x^2 -24x +63)

-2 [(x-3)(x-21)] Now divide the 7 that you multiplied earlier from 3 and 21

-2 [(x-3/7)(x-21/7)]

-2 [(7x-3)(x-3)]

Hence, the zeroes are 3/7 and 3

Hope this helps!

If you think I helped, Please mark brainliest! Would really appreciate!

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therefore, y=8x+1 seems to be very close. 
3 0
3 years ago
Given F1 = ∑ m(0,2,5,7,9) and F1 = ∑ m(2, 3,4,7,8) find the minterm expression for F1+F2. State a general rule for finding the e
Alexxandr [17]

Answer:

Step-by-step explanation:

The question tells us that;

Given F1 = ∑ m(0,2,5,7,9) and F1 = ∑ m(2, 3,4,7,8) find the minterm expression for F1+F2. State a general rule for finding the expression for F1+F2 given the minterm expansions for F1 and F2. Prove your answer by using the general form of the minterm expansion.

Note: The answer is provided in the image uploaded below

cheers i hope this helped !!!

4 0
3 years ago
Can someone help me please
babunello [35]

If the functions are inverses, then f(g(x)) = x.

A.

\displaystyle f(g(x))=f\left(\frac{3x+1}{3}\right)=\frac{1}{\frac{3x+1}{x}-3}\\\\=\frac{1}{\left(\frac{3x+1-3x}{x}\right)}=\frac{1}{\left(\frac{1}{x}\right)}=x

The functions are inverses of each other.

B. The domain of f(x) = x≠3. The domain of g(x) is x≠0.

The domain of f(g(x)) is (-∞, 0) ∪ (0, ∞).

The domain of g(f(x)) is (-∞, 3) ∪ (3, ∞).

4 0
3 years ago
Jaxon and Lucius were selling lemonade. Jaxon and Lucius have a difference of 5 cups sold. Jaxon was selling his for $6 a cup an
dimaraw [331]

Answer:

the points are (35,30) you may need to search a graph online i used desmos

Step-by-step explanation:

1.     x= Jacksons Cups   y= Lucius Cups2.       x -  y= 5           6x + 3y = 300Substitution:                                                 6 (y+5) + 3y = 300             6y + 30 + 3y = 300                9y =   270                dived both by 9                         y=30        Sub y for other equation            x - 30 = 5         add 30 to both sides           x = 35        Answer:   (35, 30)     Graphing:   x- y = 56x+ 3y = 300solve both for y y = x-5 6x + 3y = 300minus 6x from both sides the points are in y = mx + b y= 1x -5 y= -2x + 100  I will also leave the ss of the graph in the comments if you cannot see it  My labels for the x-axis is Jacksons cups and y Is luscious cups.  Elimination:x - y = 5 6x + 3y = 300 First I manipulated the equations by the following    - 6 (x - y = 5 )   1(6x  + 3y = 300 )      -6x + 6y = -30        6x + 3y  = 300          The 6 x's cancel  and add the y's and real numbers together           9y = 270           dived both by 9                   y= 30        Sub y for other equation                      x - 30 = 6                add 30 to both sides                x= 30  The points are  (35, 30) The solution is (35,30)They represent how many cups they sold.   35 is Jackson cups and 30 is Lucious's cups  

7 0
3 years ago
40. Find UW.<br> T<br> 6<br> 5<br> U +-<br> The measure of UW is<br> type your answer...
Ahat [919]

Answer:

9

Step-by-step explanation:

UT^2 = UV * UW

6^2 = (x - 7)(x - 7 + 5)

36 = (x - 7)(x - 2)

36 = x^2 - 2x - 7x + 14

x^2 - 9x - 22 = 0

(x - 11)(x + 2) = 0

x - 11 = 0  or  x + 2 = 0

x = 11

UW = x - 7 + 5

UW = 11 - 7 + 5

UW = 9

7 0
3 years ago
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