Find all real zeros of tf(x)=x-14x² + 47x-18
1 answer:
Answer:
x=3/7 and x= 3
Step-by-step explanation:
First simplify:
-14 x^2 +48x -18
divide everything by -2
-2(7 x^2 -24x +9) (Multiply the leading coefficient 7 by the constant 9)
-2 (x^2 -24x +63)
-2 [(x-3)(x-21)] Now divide the 7 that you multiplied earlier from 3 and 21
-2 [(x-3/7)(x-21/7)]
-2 [(7x-3)(x-3)]
Hence, the zeroes are 3/7 and 3
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