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a_sh-v [17]
2 years ago
12

Find three consecutive integers such that the sum of twice the smallest and 3 times the largest is 126

Mathematics
1 answer:
True [87]2 years ago
5 0

Answer:

Step-by-step explanation:

let the numbers be x,x+1,x+2   (x<x+1<x+2)

2x+3(x+2)=126

2x+3x+6=126

5x=126-6

5x=120

x=120/5=24

numbers are 24,24+1,24+2

or 24,25,26

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If x varies directly with y and x = 3.5 when y = 14, find x when y = 18.
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x = 4.5

Step-by-step explanation:

there's definitely other ways to solve this, but I used a proportion.

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The cube root of 5 times the square root of 5 over the cube root of 5 to the 5th power
Fiesta28 [93]
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Note that 5/6 - 5/3 = 5/6 - 10/6 = -5/6.

                                                            1
Thus,  5^[5/6 - 5/3] = 5^(-5/6)  =  --------------
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That's the correct answer.  But if you want to remove the fractional exponent from the denominator, do this:

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7 0
3 years ago
What is the answer??
Lemur [1.5K]

Answer:

h(3) = - 140

Step-by-step explanation:

Generate the terms in the sequence by substituting n = 2 and 3 into h(n)

h(2) = h(2 - 1) × 2 = h(1) × 2 = - 35 × 2 = - 70

h(3) = h(3 - 1) × 2 = h(2) × 2 = - 70 × 2 = - 140

8 0
3 years ago
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