A basketball court is shaped like a rectangle. It has a perimeter of 288 feet. The width of the court is 50 feet. What is the le

Question

4 years ago

8

A basketball court is shaped like a rectangle. It has a perimeter of 288 feet. The width of the court is 50 feet. What is the le

ngth of the court? Use the following formula to help you decide: Pr = 2l + 2w where Pr is the perimeter of a rectangle, l is the length, and w is the width

Mathematics

2 answers:

yawa3891 [41] · Answer 1 · 2022-01-05T20:55:36+03:00

yawa3891 [41]4 years ago

8 0

We know the perimeter and the length.
The only unknown is the length.
We write the given equation and substitute what we know.
Then we solve for what we are looking for, the length.

Pr = 2L + 2W

288 = 2L + 2(50)

288 = 2L + 100

188 = 2L

94 = L

The length is 94 ft.

ryzh [129] · Answer 2 · 2022-01-05T22:45:26+03:00

ryzh [129]4 years ago

5 0

using the given formula, fill in the numbers where they belong

perimeter = 288

width = 50

so Pr = 2l + 2w becomes

288 = 2l +2(50)

288 = 2l +100

subtract 100 from each side

188 =2l

divide both sides by 2

l = 188 /2

l = 94

length = 94 feet