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dybincka [34]
2 years ago
13

Question 1. Use the data above to construct a 95% confidence interval for the mean class size μ. (calculate y and s to 3 decimal

places). lower bound of confidence interval upper bound of confidence interval Question 2. Mark the following statement as true or false: The probability is 0.95 that the mean size μ of high school classes is contained in the interval calculated above. One submission ONLY; no exceptions. True False
Mathematics
1 answer:
snow_tiger [21]2 years ago
3 0

Answer:

Which is the output of the formula =AND(12>6;6>3;3>9)?

A.

TRUE

B.

FALSE

C.

12

D.

9

Step-by-step explanation:

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I need help please?!!!!!!
Sindrei [870]

Answer:

-2x-10 ≥ 22

Collect like terms

-2x ≥ 22+10

-2x ≥ 32

divide both sides by -2

x ≥ -16.

5 0
3 years ago
5. Write an equivalent ratio to 18:1?
Molodets [167]

Answer:

36:2

Step-by-step explanation:

we can just multiply both numbers by 2, to get 36:2

7 0
3 years ago
Read 2 more answers
What's the value of x? (Hint: it's not 7) and please explain
tekilochka [14]

Hey there!

4x + 7 + 35 = 90°

4x + 42 = 90°

SUBTRACT 42 to BOTH SIDES

4x + 42 - 42 = 90 - 42

CANCEL out: 42 - 42 because it give you 0.

KEEP: 90 - 42 because it help solve for the x-value.

NEW EQUATION: 4x = 90 - 42

SIMPLIFY IT!
4x = 48°

DIVIDE 4 to BOTH SIDES

4x/4 = 48/4

CANCEL out: 4/4 because it give you 1

KEEP: 48/4 because it give you the x-value

NEW EQUATION: x = 48/4

SIMPLIFY IT!

x = 12

Therefore, your answer is: x = 12


Good luck on your assignment & enjoy your day!



~Amphitrite1040:)

8 0
2 years ago
The width of a rectangle is two cm less than 8 times the length. The perimeter is 88 cm. What is the width and length of the rec
kati45 [8]

Let's the length to be x,

then the width is 8x - 2.

Perimeter of a rectangle = 2*Width + 2*Length

Perimeter of the rectangle = 2(8x-2) + 2x = 16x - 4 + 2x = 18x - 4

Ar the same time, Perimeter of the rectangle = 88.

So, we can write

18x - 4 = 88

18x = 84

9x=42

x= 42/9 cm (length) or ≈ 4.67 cm (length)

8x - 2 = 8*42/9 - 2 ≈ 35.33 cm (width)


6 0
3 years ago
Find the zero of f(x) = x^5-12x^2+32x
Alexeev081 [22]
The zeroes of <span>f(x) = x^5-12x^2+32x can be found by factoring,

</span><span>f(x) = x^5-12x^2+32x=(x-8)(x-4)

By the zero product theorem, (x-8)=0 or (x-4)=0 which means 
x=8 or x=4.

So the zeroes of f(x) are S={4,8}</span>
8 0
3 years ago
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