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3 years ago

Which stem-and-leaf plot represents the data 10, 70, 37, 65, 88, 86, 70, 10, 15, 15, 15?

Mathematics

2 answers:

GarryVolchara [31]3 years ago

8 0

The first one and the third one are correct

ella [17]3 years ago

3 0

A and C are correct. (plus, they're the same answers...)

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Mary measured the heights of two different plants every day. Plant A was 1 inch tall when

seropon [69]

The heights of plant A and plant B will be equal on the day 8.

<h3>How to find the heights of the trees?</h3>

The height of the tree can be found as follows:

The equation for plant A can be described as follows:

y = 1 + 0.5x

where

x = number of days

y = height

The equation for plant B can be described as follows:

y = 3 + 0.25x

Therefore, for the height to be equal

1 + 0.5x = 3 + 0.25x

1 - 3 = 0.25x - 0.5x

-2 = -0.25x

x = 2 / 0.25

x = 8 days

learn more on height here: brainly.com/question/16959984

#SPJ1

7 0

1 year ago

Flora has 33 flowers and she can pick 7 flowers a minute. Write an equation that shows how many flowers, F, that Flora will have

monitta

F=7M
33=M
Both answers will work

3 0

3 years ago

Please<br> Help !!!!!!!!!!!

slava [35]

Answer:

Painting USA is cheaper. They cost $700 dollars. The other place costs $1,000 dollars

7 0

3 years ago

3,480

Serjik [45]

Answer

explanation

3480ones = 3480x1=3480

8 0

1 year ago

Show Work Please Thank You

Misha Larkins [42]

Answer:

$\displaystyle{x = \dfrac{\pi}{12}, \dfrac{\pi}{6}}$

Step-by-step explanation:

We are given the trigonometric equation of:

$\displaystyle{\sin 4x = \dfrac{\sqrt{3}}{2}}$

Let u = 4x then:

$\displaystyle{\sin u = \dfrac{\sqrt{3}}{2}}\\\\\displaystyle{\arcsin (\sin u) = \arcsin \left(\dfrac{\sqrt{3}}{2}\right)}\\\\\displaystyle{u= \arcsin \left(\dfrac{\sqrt{3}}{2}\right)}$

Find a measurement that makes sin(u) = √3/2 true within [0, π) which are u = 60° (π/3) and u = 120° (2π/3).

$\displaystyle{u = \dfrac{\pi}{3}, \dfrac{2\pi}{3}}$

Convert u-term back to 4x:

$\displaystyle{4x = \dfrac{\pi}{3}, \dfrac{2\pi}{3}}$

Divide both sides by 4:

$\displaystyle{x = \dfrac{\pi}{12}, \dfrac{\pi}{6}}$

The interval is given to be 0 ≤ 4x < π therefore the new interval is 0 ≤ x < π/4 and these solutions are valid since they are still in the interval.

Therefore:

$\displaystyle{x = \dfrac{\pi}{12}, \dfrac{\pi}{6}}$

8 0

1 year ago