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3 years ago

What transformations were applied to ABCD to obtain A'B'C'D?

Mathematics

1 answer:

gtnhenbr [62]3 years ago

7 0

Answer:

3,5. Hope it helps and likes it

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If f(x) = x^2 + 1 and g(x) = 3x + 1, find [f(4)]^2 <br> 81 <br> 257 <br> 289

Vedmedyk [2.9K]

So g(x) doesn't come in
ok

remember pemdas
inside first
evaluate f(4)
f(4)=4^2+1=16+1=17
now we have

[17]^2=289

answer s 289

7 0

3 years ago

Read 2 more answers

in a triangle two sides of the same length the ratio of each of these sides to the third side is 5:3 if the perimeter of the tri

AveGali [126]

Answer:

Step-by-step explanation:

Perimeter of a triangle equals side 1 plus side 2 plus side 2

P = s1 + s2 + s3 side 1 = side 2 = x

x/side 3 = 5 / 3

x = (5/3) side 3

x (3/5) = side 3

perimeter = 65 slove for x

65 = x + x + 3x/5

325 = 5x + 5x + 3x

325 = 13X

25 = x equal side 1 and side 2

side 3 = 25(3/5) = 15

3 0

3 years ago

Plzzz helpppp itssss urgentt!!!!!!!!

azamat

Answer:

4) 40 Square inches

Step-by-step explanation:

You do 2 x 4 then divide by 2. after that you multiply by 4. Then you add the square which is 2 x 2

6 0

3 years ago

Vic is standing on the ground at a point directly south of the base of the CN Tower and can see the top when looking at an angle

Sindrei [870]

The angle of elevation of 61° and 72° with the height of the tower being 553.3 m. gives Vic's distance from Dan as approximately 356 meters.

<h3>How can the distance between Vic and Dan be calculated?</h3>

Location of Vic relative to the tower = South

Vic's sight angle of elevation to the top of the tower = 61°

Dan's location with respect to the tower = West

Dan's angle of elevation in order to see the top of the tower = 72°

Height of the tower = 553.3m

$tan( \theta) = \frac{opposite}{adjacent}$

$tan( 61 ^{ \circ}) = \frac{553.3}{ Vic' s\: distance \: to \: tower}$

$distance = \frac{553.3}{tan ( {61}^{ \circ} )} = 306.7$

Vic's distance from the tower ≈ 306.7 m

Similarly, we have;

$Dan's distance = \frac{553.3}{tan ( {72}^{ \circ} )} = 179.8$

Dan's distance from the tower ≈ 179.8 m

Given that Vic and Dan are at right angles relative to the tower (Vic is on the south of the tower while Dan is at the west), by Pythagorean theorem, the distance between Vic and Dan <em>d </em>is found as follows;