Can somebody please answer 3 questions for me? Even answering 1 would be great help :D Thanks in advance yall!
1 answer:
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Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.
Given:
Length of the diagonal of a quadrilateral = 8.5 cm
Lengths of the perpendiculars dropped on it from the remaining opposite vertices are 3.5 cm and 4.5 cm.
To find:
The area of the quadrilateral.
Solution:
Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths of the perpendiculars dropped on it from the remaining opposite vertices are heights of those triangles.
According to the question,
Triangle 1 : Base = 8.5 cm and Height = 3.5 cm
Triangle 2 : Base = 8.5 cm and Height = 4.5 cm
Area of a triangle is
Using this formula, we get
and
Now, area of the quadrilateral is
Therefore, the area of the quadrilateral is 34 cm².
Answer:
I did the whole graph myself so you can just couple it down lol ;)
