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ss7ja [257]
3 years ago
13

The table shows the results of rolling a number cube, with sides labeled 1 through 6, several times.

Mathematics
1 answer:
mr_godi [17]3 years ago
5 0

|\Omega|=10+6+4+8+6+6=40\\ |A|=10+6=16\\\\ P(A)=\dfrac{16}{40}=\dfrac{2}{5}=40\%

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The graph of y=⅔ x - 12 intersects the y-axis at Q (0, -12) and is perpendicular to a line joining Q to the point P ( x , 0). Fi
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They will go over point 3,0 and /4,9 then
5 0
3 years ago
A+1=1 find the value of b^a​
Ray Of Light [21]

Answer:

1

Step-by-step explanation:

a+1=1

a=1-1

a=0

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6 0
3 years ago
Read 2 more answers
I need help with this question ASAP!
mote1985 [20]
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4 0
2 years ago
The coordinates of the vertices of triangle ABC are A(−3,3), B(−1,1), and C(−3,−2). The coordinates of the vertices of the image
Annette [7]
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5 0
3 years ago
Read 2 more answers
Question 101 points)
maw [93]

Answer:

\large\boxed{y=-\dfrac{2}{3}x+\dfrac{13}{3}}

Step-by-step explanation:

\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\\\m-slope\\b-y-intercept\\\\\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\===============================

\text{We have the point:}\\\\(5,\ 1)\ \text{and}\ (-4,\ 7).\ \text{Substitute:}\\\\m=\dfrac{7-1}{-4-5}=\dfrac{6}{-9}=-\dfrac{6:3}{9:3}=-\dfrac{2}{3}\\\\\text{We have the equation in form:}\\\\y=-\dfrac{2}{3}x+b\\\\\text{Put the coordinates of the point (5, 1) to the equation:}\\\\1=-\dfrac{2}{3}(5)+b\\\\1=-\dfrac{10}{3}+b\qquad\text{add}\ \dfrac{10}{3}\ \text{to the both sides}\\\\\dfrac{3}{3}+\dfrac{10}{3}=b\to b=\dfrac{13}{3}\\\\\text{Finally:}\\\\y=-\dfrac{2}{3}x+\dfrac{13}{3}

4 0
3 years ago
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