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elena-s [515]
3 years ago
14

What’s 9+10, will give brainliest for the Awnser I’m looking for

Mathematics
2 answers:
Setler79 [48]3 years ago
6 0

Answer:

9+10 is 19 i-

Step-by-step explanation:

Sergeu [11.5K]3 years ago
4 0
Is this what you are looking for ‍♀️9+10=21
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Which graph best represents y = 10 ( 0.85 ) x ?
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Which of the following statement is true about k-NN algorithm?
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What are three different things you know about squares? List them.
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3 0
3 years ago
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) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.
yanalaym [24]

Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the  0 and 1 area equally likely to any place.

i.e. P(0)= P(1)= \dfrac{1}{2}

The length of bits : n = 10

Let X = Number of getting ones.

Then , X \sim Bin(n=10,\ p=\dfrac{1}{2})

Binomial distribution formula : P(X=x)=^nC_x p^x q^{n-x} , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , p=q=\dfrac{1}{2}

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}

=\dfrac{10!}{4!6!}(\dfrac{1}{2})^{10}+\dfrac{10!}{5!5!}(\dfrac{1}{2})^{10}

=(\dfrac{1}{2})^{10}(\dfrac{10!}{4!6!}+\dfrac{10!}{5!5!})

=(\dfrac{1}{2})^{10}(210+252)

=(0.0009765625)(462)

=0.451171875\approx0.4512

Hence, the  probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

3 0
4 years ago
9x^2 + 6x -1 =0 (Round to the nearest hundredth)
hodyreva [135]
9x^2 + 6x = 1
Factor out 3x
3x (3x +2)=1
Use the zero product property
3x=1
3x+2 = 1
X= +1/3 and -1/3
7 0
3 years ago
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