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irinina [24]
3 years ago
11

You create a game that uses the spinner shown

Mathematics
1 answer:
Whitepunk [10]3 years ago
3 0

Answer:

\dfrac{2}{3}

Step-by-step explanation:

Conditional Probability:

P(A|B)=\dfrac{P(A \cap B)}{P(B)}

From the spinner shown, there are 10 sections.

P(< 6)=6/10\\P(Yellow)=3/10

P($Yellow and $

Therefore:

P(< 6 | \text{Yellow})=\dfrac{P(

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You invest $300 at 4% interest, compounded every year. What will your balance be after 5 years? (Remember, the formula is A = P(
Stells [14]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill\\ P=\textit{original amount deposited}\to &\$300\\ r=rate\to 4\%\to \frac{4}{100}\to &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{every year, once} \end{array}\to &1\\ t=years\to &5 \end{cases} \\\\\\ A=300\left(1+\frac{0.04}{1}\right)^{1\cdot 5}\implies A=300(1.04)^5\implies A\approx 364.996

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3 years ago
Question 8 of 10 What is the median of this data set? 14, 18, 31, 34, 44, 50 A. 32.5 B. 33 C. 31.5 O O D. 31 SUBM​
kozerog [31]

Answer:

32.5

Step-by-step explanation:

median is the middle number, in this case the sum of the two middle number divided by 2

31 + 34 = 65/2

32.5

8 0
3 years ago
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What is 10x and a negative 15 over 10 plus one half
eimsori [14]

Answer:

-29/2

Step-by-step explanation:

3 0
3 years ago
Convert (1, 1) to polar form.<br> A. (2,459<br> B. (1,459)<br> C.(2, 2259)<br> D.(72,459)
timama [110]

Polar form: (r,θ)

Using these formulas:

x²+y²=r²

tan(θ)=y/x

We have the point (1,1) in cartesian coordinates. We need to find r and θ to get it in polar form.

r²=1²+1²

r²=2

r=±√2

tan(θ)=1/1

tan(θ)=1

θ=π/4 radians or 45 degrees

Polar coordinates: (√2,π/4)

Those answer choices look strange. Are you sure these are the right answer choices?

5 0
3 years ago
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For the functions f(x)=−7x^2−x and g(x)=9x^2−4x, find (f−g)(x) and (f−g)(1)
musickatia [10]

Answer:

See below.

Step-by-step explanation:

f(x)=-7x^2-x\\g(x)=9x^2-4x\\(f-g)(x)=f(x)-g(x)\\(f-g)(x)=(-7x^2-x)-(9x^2-4x)\\(f-g)(x)=-7x^2-x-9x^2+4x\\(f-g)(x)=-16x^2+3x\\\\(f-g)(1)=-16(1)^2+3(1)\\(f-g)(1)=-16+3=-13

5 0
3 years ago
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