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Lelechka [254]
3 years ago
13

Write an expression using multiplication and addition with the sum of 16

Mathematics
2 answers:
Rudiy273 years ago
6 0
There are many answers for this and this is one of them:
Y = 4(3 + 1)
Y = 16
vagabundo [1.1K]3 years ago
5 0
Lot of answers m8 mine is
2(6+2)
=16
You might be interested in
20)
Nataly [62]

Answer:

babysitting = $9

working at coffeehouse = $12

x = hours for babysitting

y = hours at coffeehouse

minimum = ≥

9x + 12y ≥ 240

Step-by-step explanation:

just a short note on which symbol you should use when you see these words in inequality questions:

i) use ≥

-more than or equal to

-not less than

-at least

-minimum

ii) use >

-more than

-greater than

iii) use ≤

-less than or equal to

-not more than

-at most

-maximum

iv) use <

-less than

7 0
2 years ago
What is the slope-intercept form of this equation?
quester [9]
8X+6Y=12

Here's how you solve it:

Just isolate y by itself to get y-intercept form.
This is the formula: Y=MX+B

M is the slope or the number next to X in the original problem.

First:
6Y=-8X+12

Next:
divided everything by 6

Y=-4/3+2

I think the answer is A!


3 0
3 years ago
Read 2 more answers
Would my answer be c or a
mylen [45]

the answer is c

the y-intercept is 10–it doesn’t have a negative sign, so it is positive

4 0
3 years ago
An equation that is true when y=-0.5
KIM [24]
2y+1=0.5+y.

Hope this helps!
3 0
3 years ago
With a detailed explanation from the internet<br> 1/(x-5)+3/(x+2)=4
irga5000 [103]

Answer:

\boxed{ \sf x=\dfrac{4\pm\sqrt{43}}{2}}

Explanation:

\rightarrow \sf \dfrac{1}{x-5}+\dfrac{3}{x+2}=4

<u>make the denominators same</u>

\rightarrow \sf \dfrac{1(x+2)}{(x-5)(x+2)}+\dfrac{3(x-5)}{(x+2)(x-5)}=4

<u>join the fractions together</u>

\rightarrow \sf \dfrac{x+2+3x-15}{(x-5)(x+2)}=4

<u>cross multiply</u>

\rightarrow \sf x+2+3x-15=4(x-5)(x+2)

<u>simplify</u>

\rightarrow \sf 4x-13=4x^2-12x-40

<u>group the variables</u>

\rightarrow \sf 4x^2-16x-27 = 0

<u>use quadratic formula</u>

\rightarrow \sf x = \dfrac{-\left(-16\right)\pm \sqrt{\left(-16\right)^2-4\cdot \:4\left(-27\right)}}{2\cdot \:4}

<u>simplify the following</u>

\rightarrow \sf x=\dfrac{4\pm\sqrt{43}}{2}

7 0
2 years ago
Read 2 more answers
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