By how much would its speed reading increase with each second of fall? ... Ex 3.24 For a freely falling object dropped from rest, what is its acceleration at the end of the 5th second ... Pb 3.3 A ball is thrown straight up with an initial speed of 30 m/s. How high does it go, and how long is it in the air (neglecting air resistance)?.
An electron is emitted in both positive and negative beta decay, although the positive one is called positron emission.
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Answer:
1. t = 3.27 seconds
2. y = 147.3 m
Explanation:
Newton's Laws of Motions.
y = v₁t + 1/2 at²
a = (v₂-v₁)/t
where
y = the vertical distance travelled
v₁ = the initial velocity
v₂ = the final velocity
t = the time
a = the acceleration
final velocity is equal to 0.
So, v₂ = 0.
a = (v₂-v₁)/t
a = (0-30)/t
a = -30/t
plugin values into the first equation:
y = v₁t + 1/2 at²
49 = 30t + 1/2 (-30/t)t²
49 = 30t -15t
49 = 15 t
t = 49/15
t = 3.27 seconds
2.
y = v₁t + 1/2 at²
a = -30/3.27
a = 9.2
y = 30(3.27) + 1/2(9.2) 3.27²
y = 147.3 m
Answer:
continue moving with constant velocity
Explanation: