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3 years ago

Which object is hotter? Multiple Choice -22:49 O Object 1 at T = 0°C Object 3 at T = OK Object 2 at T = 0°F

Physics

1 answer:

krek1111 [17]3 years ago

8 0

Answer:

Object 1 is hotter.

Explanation:

Object 1 T= $0^{\circ}C$

Object 2 T=0 K

Object 3 T= $0^{\circ}F$

Relation between Celcius ,Kelvin and Fahrenheit

$\dfrac{C-0}{100}=\dfrac{K-273}{100}=\dfrac{F-32}{180}$

K=C+273, $K=\dfrac{5}{9}(F-32)+273$ .

So now we will convert all in one unit.

Object 1 T=273 K

Object 2 T=0 K

Object 3 T=255.22 K

From above we can say that Object 2 is coolest and object 1 is hottest.

So Object 1 is hotter.

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Uma chapa metálica, com um furo central de diâmetro "d", é aquecida dentro de um forno. Com o aumento da temperatura, podemos af

Tatiana [17]

Answer: O furo diminui enquanto a chapa aumenta a sua dimensão.

(The diameter decreases and the dimensions of the metal increases)

Explanation:

I will answer in English:

Here we have a piece of metal with a small hole on it, that is heated in a hoven.

We know that when a piece of metal is heated, it will expand (the density decreases, so the dimensions of the piece of metal increase).

Now, particularly, the hole will also expand but inwards, as each "extreme" of the piece of metal, will expand into where it has less resistance, so it will expand in the region where there is no material. This "inwards" expansion is why the diameter of the hole will decrease.

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3 years ago

Use Percentages Given that the molecular mass of magnesium

ira [324]

Answer:

27%

Explanation:

15.999 divided by 58.32 = .27433128

Move the decimal place over 2 places.

27%

5 0

4 years ago

A 0.300 kg block is pressed against a spring with a spring constant of 8050 N/m until the spring is compressed by 6.00 cm. When

natita [175]

Answer:

a) $\mu_{k} = 0.704$ , b) $R = 0.312\,m$

Explanation:

a) The minimum coeffcient of friction is computed by the following expression derived from the Principle of Energy Conservation:

$\frac{1}{2}\cdot k \cdot x^{2} = \mu_{k}\cdot m\cdot g \cdot \Delta s$

$\mu_{k} = \frac{k\cdot x^{2}}{2\cdot m\cdot g \cdot \Delta s}$

$\mu_{k} = \frac{\left(8050\,\frac{N}{m} \right)\cdot (0.06\,m)^{2}}{2\cdot (0.3\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (7\,m)}$

$\mu_{k} = 0.704$

b) The speed of the block is determined by using the Principle of Energy Conservation:

$\frac{1}{2}\cdot k \cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}$

$v = x\cdot \sqrt{\frac{k}{m} }$

$v = (0.06\,m)\cdot \sqrt{\frac{8050\,\frac{N}{m} }{0.3\,kg} }$

$v \approx 9.829\,\frac{m}{s}$

The radius of the circular loop is:

$\Sigma F_{r} = -90\,N -(0.3\,kg)\cdot (9.807\,\frac{m}{s^{2}} ) = -(0.3\,kg)\cdot \frac{v^{2}}{R}$

$\frac{\left(9.829\,\frac{m}{s}\right)^{2}}{R} = 309.807\,\frac{m}{s^{2}}$

$R = 0.312\,m$

5 0

4 years ago

A circuit contains four capacitors in parallel (10 F, 3 F, 7 F, and 1 F). What is the equivalent capacitance of this circuit?

goldfiish [28.3K]

The equivalent capacitance of this circuit is = 21F. That is option A.

<h3>Calculation of the equivalent capacitance</h3>

When capacitors are connected together in parallel the total or equivalent capacitance, CT in the circuit is equal to the sum of all the individual capacitors added together.

The four capacitors are 10 F, 3 F, 7 F, and 1 F.

Therefore the equivalent capacitance = 10 + 3 + 7 + 1=21F

Learn more about capacitance here:

brainly.com/question/13578522

#SPJ1

7 0

2 years ago

A voltmeter reads 200 V between parallel plates that are 2 cm apart. what is the strength of the electric field between the two

Misha Larkins [42]

I think that is c) l’m not sure

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3 years ago