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Sergio [31]
4 years ago
6

Enter the midpoint of the segment whose endpoints are (2,5) and (-4,12)

Mathematics
1 answer:
Alexus [3.1K]4 years ago
5 0

Answer:

The answer is

<h2>( - 1 \: , \:  \frac{17}{2} )</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

<h3>M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )</h3>

From the question the points are

(2,5) and (-4,12)

The midpoint is

M = ( \frac{ 2 - 4}{2}   \: , \:  \frac{5 + 12}{2} )  \\  = ( -  \frac{2}{2}  \: , \:  \frac{17}{2} )

We have the final answer as

( - 1 \: , \:  \frac{17}{2} )

Hope this helps you

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⠀

Step-by-step explanation:

The triangle having two sides equal along with one different side is called an isosceles triangle.

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  • So, Let us assume the other sides (two equal sides) of the isosceles triangle as x. As the different side is already given in the question.

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We know that,

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So, According to the question :

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{\longrightarrow \it\qquad { \ { {  38 \: }^{ \circ}   + x + x  =  180{}^{ \circ} }}}

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{\longrightarrow \it\qquad { \ { {  38 \: }^{ \circ}   + 2x   =  180{}^{ \circ} }}}

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{\longrightarrow \it\qquad { \ {   2x   =  180{}^{ \circ} - {  38 \: }^{ \circ}}}}

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{\longrightarrow \it\qquad { \ {   2x   =  142{}^{ \circ}  }}}

⠀

{\longrightarrow \it\qquad { \ {   x   =    \dfrac{142{}^{ \circ}}{2}   }}}

⠀

{\longrightarrow \it\qquad { \pmb {   x   =  71^{ \circ}  }}}

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Therefore,

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