The maximum value can be determined by taking the derivative of the function.
(dh/dt) [h(t)] = h'(x) = -9.8t + 6
Set h'(x) = 0 to find the critical point
-9.8t + 6 = 0
-9.8t = -6
t = 6/9.8
Plug the time back into the function to find the height.
h(6/9.8) = -4.9(6/9.8)^2 + 6(6/9.8) + .6
= 2.4
And I don't understand your second question.
120/6=20 20*10=200
The answer is 200
D is the answer to your question
Answer: g(f(h)) = pie(200h)^2
Step-by-step explanation:
Answer:
3/4
Step-by-step explanation:
We can use the slope formula when given two points
m = ( y2-y1)/(x2-x1)
= ( 5-2)/(1 - -3)
= (5-2)/(1+3)
= 3/4
