We are given 3 equations. Using these equations we can find f(h(2)).
h(x)=7x-5
h(2)=7(2)-5
h(2)=14-5
h(2)=9
f(x)=x^2-7
f(h(2))=(7x-5)^2-7
we know the answer for h(2) by now, so we can substitute for that.
f(9)=9^2-7
f(9)=81-7
f(9)=74
so f(h(2))=74
Answer:
Step-by-step explanation:
Subtract the 4 from 9
3. Answer: a) RT
b) XZ
c) TS
4. Answer: a) 26
b) 58
c) 21.5
d) 127
<u>Step-by-step explanation:</u>
2(PT) = AE 2(CP) = AN 2(CT) = EN
2(13) = AE 2(29) = AN 2(CT) = 43
26 = AE 58 = AN CT = 21.5
Perimeter = AE + AN + EN
= 26 + 58 + 43
= 127
Answer:
60.1
Step-by-step explanation:
Just get 72.60 and subtract 12.50
