Question

You are flying a kite. You have let out 28 feet of string. If the angle that the kite’s string makes with the ground is 52°, how high above the ground is the kite? Round to the nearest foot. You must show your work to receive credit.

Answer 1

Answer:

Height$=22\ feet$

Step-by-step explanation:

Let Kite is at point $Q$ and My place is $P$.

$PQ=length\ of\ string=28\ feet$

Let $RQ$ be height and it is$=h\ feet$

$\angle QPR=52\textdegree$

$Now\ in\ \triangle PQR\\\\\sin \angle QPR=\frac{Opposite}{Hypotenuse}=\frac{QR}{PQ}\\\\\sin 52=\frac{h}{28}\\\\h=28\times \sin 52\\\\h=28\times 0.7880\\\\h=22.064\approx 22\ feet$