Answer:
The perimeter of triangle PQR is 17 ft
Step-by-step explanation:
Consider the triangles PQR and STU
1. PQ ≅ ST = 4 ft (Given)
2. ∠PQR ≅ ∠STU (Given)
3. QR ≅ TU = 6 ft (Given)
Therefore, the two triangles are congruent by SAS postulate.
Now, from CPCTE, PR = SU. Therefore,

Now, side PR is given by plugging in 3 for 'y'.
PR = 3(3) - 2 = 9 - 2 = 7 ft
Now, perimeter of a triangle PQR is the sum of all of its sides.
Therefore, Perimeter = PQ + QR + PR
= (4 + 6 + 7) ft
= 17 ft
Hence, the perimeter of triangle PQR is 17 ft.
The answer to this is 660
6 divided by 2 and 1 forths is going to be 8 out of 3
<h3>What are trigonometric ratios?</h3>
Trigonometric ratios are defined as the ratio of different sides of a right angle triangle with respect to one angle of the right angled triangle.
Length of the wire = Hypotenuse of the triangle = X
Base of the triangle = Distance from the bottom of the tower to the point where wire is attached on ground = 20 m
Angle b/w Hypotenuse and Base of triangle = 46°
cos(θ) = Base / Hypotenuse
cos(46) = 20 / X
X = 20 / cos(46)
X = 28.79 m
Hence, the length of the wire is 28.79 m.
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First we find the unit rate which would be how many words in 1 minute...
294/7 = 294 ÷ = 42 wpm
Now we multiply by how many minutes to find the total...
42 wpm × 11 min = 462 words.