The length of a rectangle is 3 less than 2 times its width. The area of the rectangle is 77 squared feet.
1 answer:
Answer:
Let the Width(W) =X feet
then Length(L) = (2X-3)feet
Area of the rectangle (A)=77 square feet
A = L× W
L×W=A
(2X-3) × X = 77
2X²- 3X =77
2X²-3X -77=0
Solving it using the factorization method
2X²-14X+11X-77=0
(2X²-14X)+(11X-77)=0
2X(X-7) + 11(X-7)=0
(2X+11)(X-7) =0
When 2X+11=0
X= -11/2
When X-7=0
X = 7
Therefore X= 7
Width = X feet
= 7feet
The width is 7feet
Length = (2X-3)feet
= (2×7) -3)feet
=(14-3)feet
=11feet
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This answer is not represented in the pictures you attached
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