Question

The length of a rectangle is 3 less than 2 times its width. The area of the rectangle is 77 squared feet.

Answer 1

Answer:

Let the Width(W) =X feet

then Length(L) = (2X-3)feet

Area of the rectangle (A)=77 square feet

A = L× W

L×W=A

(2X-3) × X = 77

2X²- 3X =77

2X²-3X -77=0

Solving it using the factorization method

2X²-14X+11X-77=0

(2X²-14X)+(11X-77)=0

2X(X-7) + 11(X-7)=0

(2X+11)(X-7) =0

When 2X+11=0

X= -11/2

When X-7=0

X = 7

Therefore X= 7

Width = X feet

= 7feet

The width is 7feet

Length = (2X-3)feet

= (2×7) -3)feet

=(14-3)feet

=11feet