Answer:
z(max) = 256000 Php
x₁ = 10
x₂ = 110
Step-by-step explanation:
Jogging pants design Selling Price Cost
weekly production
Design A x₁ 2500 1750
Design B x₂ 2100 1200
1. z ( function is : )
z = 2500*x₁ + 2100*x₂ to maximize
First constraint weekly production
x₁ + x₂ ≤ 120
Second constraint Budget
1750*x₁ + 1200*x₂ ≤ 150000
Then the model is
z = 2500*x₁ + 2100*x₂ to maximize
Subject to
x₁ + x₂ ≤ 120
1750*x₁ + 1200*x₂ ≤ 150000
General constraints x₁ ≥ 0 x₂ ≥ 0 both integers
First table
z x₁ x₂ s₁ s₂ cte
1 -2500 -2100 0 0 0
0 1 1 1 0 = 120
0 1750 1200 0 1 = 150000
Using AtoZmath online solver and after 6 iterations the solution is:
z(max) = 256000 Php
x₁ = 10
x₂ = 110
Answer:
study lol
Step-by-step explanation:
3x-4 = -10
3x-4 +4 = -10 +4
3x = -6
then you can divide it :
x = -6 : 3
x= -2
#6
D. 3.0 x 10^8
#7
A. y = 3.5x + 7
#8
B. 5
